Magnitude and angles of a force

Click For Summary
The force vector is given as F = 20i - 60j + 90k N, and its magnitude is calculated to be 110 N. The angles formed with the coordinate axes are approximately 79.5 degrees with the x-axis, 123.1 degrees with the y-axis, and 35.1 degrees with the z-axis. The calculations for magnitude and angles appear correct, but discrepancies with textbook answers may arise from differences in angle measurement units, such as radians. Overall, the solution provided is accurate and valid.
IHave
Messages
21
Reaction score
0

Homework Statement


a force is given by F= 20i - 60j + 90k N. Find its magnitude and the angles it forms with the coordinate axis.

Homework Equations


F = magnitude of F times the unit vector
magnitude is square root (Fx squared + Fy squared + Fz squared)
and the unit vector can be written as (cos(theta)x)i + (cos(theta)y)j + (cos(theta)z)k
x for x component
y for y component
z for z component

to find the angle of the x component: inverse cosine of Fx/magnitude

The Attempt at a Solution


For the magnitude I got 110
for the angles with respect to x, y, z: 79.5, 123.1, 35.1

please tell me if i did something wrong! thanks
 
Physics news on Phys.org
That should be correct.
 
IHave said:

Homework Statement


a force is given by F= 20i - 60j + 90k N. Find its magnitude and the angles it forms with the coordinate axis.

Homework Equations


F = magnitude of F times the unit vector
magnitude is square root (Fx squared + Fy squared + Fz squared)
and the unit vector can be written as (cos(theta)x)i + (cos(theta)y)j + (cos(theta)z)k
x for x component
y for y component
z for z component

to find the angle of the x component: inverse cosine of Fx/magnitude

The Attempt at a Solution


For the magnitude I got 110
for the angles with respect to x, y, z: 79.5, 123.1, 35.1

please tell me if i did something wrong! thanks

Agree. All looks good.
 
If a textbook or something gives a different answer, it's possible the angle is in another measurement, for example radians.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

Replies
4
Views
814
  • · Replies 6 ·
Replies
6
Views
2K
Replies
1
Views
1K
Replies
3
Views
1K
  • · Replies 8 ·
Replies
8
Views
707
  • · Replies 16 ·
Replies
16
Views
2K
Replies
14
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 18 ·
Replies
18
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K