Magnitude and direction of the resultant force

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SUMMARY

The discussion focuses on calculating the magnitude and direction of resultant forces and velocities in physics problems involving vectors. The first problem involves three forces exerted on a box, resulting in a force of 142.6 N at an angle of 165.2 degrees. The second problem calculates the resultant velocity of a boat crossing a river, yielding a velocity of 8.5 m/s at an angle of 289.3 degrees, with a momentum of 1623 kg·m/s. The importance of including directional information in momentum calculations is emphasized.

PREREQUISITES
  • Understanding of vector components and their resolution
  • Knowledge of trigonometric functions for angle calculations
  • Familiarity with momentum and its directional properties
  • Basic principles of physics related to forces and motion
NEXT STEPS
  • Study vector resolution techniques in physics
  • Learn about momentum calculations and their implications
  • Explore the use of trigonometry in determining angles in physics problems
  • Investigate real-world applications of resultant forces in engineering
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Students studying physics, particularly those focusing on mechanics, as well as educators and anyone interested in vector analysis and its applications in real-world scenarios.

Klutch
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1. Three ropes are tied to a box and three boys exert the following forces:
F1=220 N @ 90 degrees
F2=185 N @ 165 degrees
F3=235 N @280 degrees

Determine the magnitude and direction of the resultant force.

For my solution I made a Vector Componant table, found the total force on the x and y axis. Transferred that to a diagram and found the resultant force to be 142.6 N in a direction of 165.2 degrees.

2. You head across the Battle River in your boat with a velocity of 8.0 m/s, south. The river is flowing at 2.8 m/s, east.

a) Determine the magnitude and the direction of the resultant velcity vector.
b)Assume that you and you boat have a total mass of 192 kg. Calculate the direction of the momentum of you and your boat as you cross the river.

This question seemed to be really simple. I got the resultant velocity to be 8.5 m/s in a direction of 289.3 degrees. For the next part I found the momentum to be 1623 kgm/s, and wouldn't the direction be the same as the velocity?
 
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Yeah, I didn't check it but it looks as though everything is correct. For the boat you should include the direction (i.e. 19.3 degrees east of south or whatever the angle was relative to).
 
Last edited:
Alright Thanks, and a little heads up for everyone here. I'll be one these forums a lot, because I'm taking Physics by correspondance.
 

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