Magnitude of angular acceleration- my first post ever in physics forum

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Homework Help Overview

The problem involves calculating the magnitude of angular acceleration for a CD that plays for 74 minutes, starting at an angular speed of 480 rpm and slowing to 210 rpm.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to convert angular velocities from revolutions per minute to radians per second and calculates angular acceleration. Some participants question the accuracy of the final angular velocity conversion and encourage clarification of the calculations.

Discussion Status

Participants are actively discussing the calculations, with some guidance provided regarding the interpretation of magnitude in the context of angular acceleration. There is an acknowledgment of the original poster's confusion regarding the sign of the result.

Contextual Notes

There is a mention of the original poster's first post in the forum, indicating a learning context. The discussion includes potential errors in unit conversion and the interpretation of the term "magnitude."

sweetwilliam
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Homework Statement



CD is playing for 74 min, starts at angular speed of 480 rpm then slows to 210rpm. what's the magnitude of the angular acceleration

Homework Equations


angular acceleration =ω/ t


The Attempt at a Solution


i converted the rev to rad then min to sec then divided by sec and got 50.3 rad/s and 14.7 rad/s ... 14.7-50.3=-35.6/4440s= -.0080 my book says its wrong...fyi this is my first pot in physics forum so i hope i did it all correct
 
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Hi sweetwilliam , welcome to Physics Forums.

Your initial angular velocity value looks okay at 50.3 rad/s. You might want to check your value for the final angular velocity.
 
Hi, thanks...i re-did the final rev/min and got 29.43 but when i put that back into my formula I am still not getting the answer that's in the book...thanks
 
sweetwilliam said:
Hi, thanks...i re-did the final rev/min and got 29.43 but when i put that back into my formula I am still not getting the answer that's in the book...thanks

That value, 29.43, still doesn't look quite right. Can you expand on your calculation?
 
i took 281rev/min and multiplied it by 2pi then divided by 60 sec...thanks
 
oh sorry i meant 210 rev.min x 2pi then divide by 60 which =21.99
 
ok after using that number i got -.0064 rad/s^2 which is partially correct by why in the book does it say .0064, where did the neg. go?
 
sweetwilliam said:
ok after using that number i got -.0064 rad/s^2 which is partially correct by why in the book does it say .0064, where did the neg. go?

They asked for the magnitude of the acceleration. Magnitudes are always positive.
 
OOOHHH yes ok gottcha thanks
 

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