Torque and angular acceleration pulley problem

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SUMMARY

The discussion focuses on calculating the angular acceleration and angular velocity of a solid cylindrical pulley with a mass of 5 kg and a radius of 0.6 m, subjected to a tangential force of 30 N. The correct angular acceleration is determined to be 20 rad/sec², while the angular velocity after 3 seconds is 60 rad/sec. The initial calculations incorrectly used the moment of inertia for a hollow cylinder instead of the solid cylinder, leading to discrepancies in the results.

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BrainMan
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Homework Statement


A pulley in the shape of a cylinder of mass 5 kg and radius 0.6 m has a force of magnitude 30 N exerted tangentially on it. Find the angular acceleration of the pulley and its angular velocity after 3 s, assuming it starts from rest.

Homework Equations


T = Ftr
T = mr^2a



The Attempt at a Solution


(a) I tried to find the acceleration using torque equations
T = FtR
T = 30(.6)
T=18

T = mr^2a
18 = 5(.36)a
a = 10 rad/sec^2

(b) Then I took the acceleration and tried to find the angular velocity
ω = ωi + at
ω = 10(3)
ω = 30 rad/sec

They correct answer is (a) 20 rad/sec^2 (b) 60 rad/sec
 
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BrainMan said:
T = mr^2a
18 = 5(.36)a
a = 10 rad/sec^2

You have used MI of a hollow cylinder whereas pulley is a solid cylinder .Use Moment of inertia of solid cylinder .
 
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Tanya Sharma said:
You have used MI of a hollow cylinder whereas pulley is a solid cylinder .Use Moment of inertia of solid cylinder .

I got it right. Thanks!
 

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