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Torque and angular acceleration pulley problem

  • Thread starter BrainMan
  • Start date
279
2
1. Homework Statement
A pulley in the shape of a cylinder of mass 5 kg and radius 0.6 m has a force of magnitude 30 N exerted tangentially on it. Find the angular acceleration of the pulley and its angular velocity after 3 s, assuming it starts from rest.

2. Homework Equations
T = Ftr
T = mr^2a



3. The Attempt at a Solution
(a) I tried to find the acceleration using torque equations
T = FtR
T = 30(.6)
T=18

T = mr^2a
18 = 5(.36)a
a = 10 rad/sec^2

(b) Then I took the acceleration and tried to find the angular velocity
ω = ωi + at
ω = 10(3)
ω = 30 rad/sec

They correct answer is (a) 20 rad/sec^2 (b) 60 rad/sec
 
1,540
134
T = mr^2a
18 = 5(.36)a
a = 10 rad/sec^2
You have used MI of a hollow cylinder whereas pulley is a solid cylinder .Use Moment of inertia of solid cylinder .
 
Last edited:
279
2
You have used MI of a hollow cylinder whereas pulley is a solid cylinder .Use Moment of inertia of solid cylinder .
I got it right. Thanks!
 

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