Magnitude of Cable Tensions and Compressive Force

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SUMMARY

The discussion focuses on calculating the magnitudes of cable tensions and compressive forces in a static system involving a beam and cables. The user calculates the compression at point BC as 8495N and the tension in cable AC as 8890N using the equations mg*sin(60) and mg*cos(25), respectively. The user seeks clarification on the direction of reaction forces at point C, specifically for the beam and both sections of the cable. The analysis emphasizes the importance of understanding the physical implications of force directions in static equilibrium.

PREREQUISITES
  • Understanding of static equilibrium principles
  • Knowledge of trigonometric functions in physics
  • Familiarity with free body diagrams
  • Basic mechanics of materials, specifically tension and compression
NEXT STEPS
  • Study static equilibrium problems involving multiple forces
  • Learn about free body diagram construction and analysis
  • Explore the concepts of tension and compression in cables and beams
  • Investigate the application of trigonometric functions in force resolution
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Students in physics or engineering courses, particularly those studying mechanics, as well as professionals involved in structural analysis and design.

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Homework Statement


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There's a diagram with a rough free body diagram implemented.


Homework Equations



This is what I'm really unsure about.


The Attempt at a Solution



Finding Compression at BC: mg*sin(60) = 8495N
Tension AC = mg*cos(25) = 8890N

Not sure if that's right, but, it's all I can come up with!

Please help!
 
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At point C, what is the direction of:

1. The reaction force of the beam?
2. The reaction force of the upper part of the cable?
3. The force applied by the lower part of the cable?
 
How do I find them?
 
Each of those has only two possibilities. Consider both, choose one that makes physical sense.
 

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