- #1
sonastylol
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[SOLVED] Magnitude of Single Displacement:
Please bear with me, I'm going to try and properly format this, so you forum-goers actually want to help me out.
A novice golfer on the green takes three strokes to sink the ball. The successive displacements are 7.4 m to the north, 2.8 m northeast, and 9.9 m 79degreeswest of south. Starting at the same initial point, an expert (lucky) golfer could make the hole in a single displacement. What is the magnitude of this single displacement? Answer in units of m.
Magnitude = [tex]\sqrt{(axi)^2 + (ayj)^2}[/tex]
For this equation:
Magnitude of A: [tex]\sqrt{(0)^2 + (7.4)^2}[/tex]
Magnitude of B: [tex]\sqrt{(2.8cos45)^2 + (2.8sin45)^2}[/tex]
Heres the tricky part:
Vector C is described as 9.9m 79 degrees west of south. Does this make it 191 degrees?
If yes: Vector C should be: [tex]\sqrt{(9.9cos191)^2 + (9.9sin191)^2}[/tex]
I then add up the values of Magnitude A, B, C to get the answer... yes?
Thanks for your time.
Please bear with me, I'm going to try and properly format this, so you forum-goers actually want to help me out.
Homework Statement
A novice golfer on the green takes three strokes to sink the ball. The successive displacements are 7.4 m to the north, 2.8 m northeast, and 9.9 m 79degreeswest of south. Starting at the same initial point, an expert (lucky) golfer could make the hole in a single displacement. What is the magnitude of this single displacement? Answer in units of m.
Homework Equations
Magnitude = [tex]\sqrt{(axi)^2 + (ayj)^2}[/tex]
The Attempt at a Solution
For this equation:
Magnitude of A: [tex]\sqrt{(0)^2 + (7.4)^2}[/tex]
Magnitude of B: [tex]\sqrt{(2.8cos45)^2 + (2.8sin45)^2}[/tex]
Heres the tricky part:
Vector C is described as 9.9m 79 degrees west of south. Does this make it 191 degrees?
If yes: Vector C should be: [tex]\sqrt{(9.9cos191)^2 + (9.9sin191)^2}[/tex]
I then add up the values of Magnitude A, B, C to get the answer... yes?
Thanks for your time.