Magnitude of the charge on the oil drop

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SUMMARY

The magnitude of the charge on an electrically charged oil drop with a mass of 5.449x10-14 kg, suspended in a uniform electric field of 1.667x106 N/C, is calculated using the formula q = Mg/E. Substituting the values, the charge is determined to be 3.203x10-19 C. This confirms that the oil drop remains at rest due to the balance of gravitational and electric forces acting on it.

PREREQUISITES
  • Understanding of electric fields and forces
  • Basic knowledge of mass and weight calculations
  • Familiarity with the formula q = Mg/E
  • Concept of charge in electrostatics
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  • Learn about the behavior of particles in electric fields
  • Investigate the applications of oil drop experiments in measuring charge
  • Study the effects of varying electric field strengths on charged particles
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bphy
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1. An electrically charged macroscopic spherical oil drop of mass M=5.449x10^(-14) kg is released from rest between two electrically charged horizontal plates that produce a uniform electric field magnitude of E=1.667x10^6 N/C that is directed vertically upward. If, after release, the oil drop remains at rest, what is the the magnitude of the charge on the oil drop?



2. The attempt at a solution:

qE=Mg

q= Mg/E

q= (5.449x10^-14)(9.8)/(1.667x10^6)

q=3.203x10^-19 C ----> is this the magnitude of the charge?
 
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