Magnitude of the Force of Friction

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Homework Help Overview

The discussion revolves around the magnitude of the force of friction acting on a wooden crate being dragged across a floor at a constant speed. Participants are exploring concepts related to Newton's laws of motion and the relationship between applied forces and frictional forces.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the implications of constant speed motion and question the role of acceleration. There are attempts to relate the net force to the applied force and friction. Some participants suggest drawing free body diagrams to visualize the forces involved.

Discussion Status

The discussion is active, with participants providing hints and engaging in reasoning about the forces at play. There is some disagreement regarding the interpretation of the forces, particularly concerning the relationship between the pulling force and the force of friction.

Contextual Notes

Participants are navigating the constraints of the problem setup, including the constant speed condition and the implications of no acceleration on net force calculations. There is also a shift in focus to a different problem involving a painter and forces, indicating a broader exploration of related concepts.

Helpme7534
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A wooden crate with a mass of 20.0 kg is dragged across a floor at a constant speed by a force of 85.0N. The magnitude of the force of friction here is ____ N.

I'm not even sure how to start.
 
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What do Newton's laws say about constant speed motion?
 
F=ma
 
no acceleration?
 
Helpme7534 said:
no acceleration?
If it is dragged with constant speed, yes. Try to draw a free body diagram and find forces acting on the object. Now let's see. I can first find two forces.
Hint: 'apple and Newton', and [the block is being moved by what?]
 
k i appreciate the help but i need to no how to do it,
f=ma yes i no that, but i don't no how to get force of friction
 
If there is no acceleration, what is the net force?
 
85n?
 
no... you have information that there is no acceleration. so a=0 plug that in f(net)=ma. What is net force now?
 
  • #10
0, so 85 N is the force of friction?
 
  • #11
Yes, zero. But Sorry, force of friction is not 85n. We are pulling this with 85n. If force of friction equals the force pulling, the object won't move. Take a look at your another post in which I submitted by opinion.
 
  • #12
Whoa I think you're wrong there stanton...and Helpme7534 is right. Don't confuse the guy.

If force of friction equals the force pulling, the object will move if it was already moving.
 
  • #13
A Painter of Mass 70kg stands on a platform of mass 10kg and pulls himself with an acceleration of 10 cm/sec^2. He pulls each rope with a force F as shown below.

a). Draw a free body diagram for the painter.
b). Compute the value of F.
c). Compute the contact force which the painter exerts on the platform.

(sorry i couldn't draw the image. which is man pulling down the two ropes from two directions.)
 

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