Making Amplitude of Oscillation the Same

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SUMMARY

The discussion centers on determining the conditions under which two different masses oscillate with the same amplitude. The key equation derived is (x0)^2 + (w*v0)^2, which is essential for establishing equal amplitudes. Participants clarify that the amplitude (A) must be the same for both masses, and they explore the implications of substituting values into the equations of motion x(t) = A*cos(wt + p) and v(t) = -A*w*sin(wt + p). The correct formulation for equal amplitudes is confirmed to be (x0)^2 + (v0/w)^2.

PREREQUISITES
  • Understanding of harmonic motion equations, specifically x(t) = A*cos(wt + p)
  • Familiarity with angular frequency (w) and its role in oscillation
  • Knowledge of initial conditions in oscillatory systems, such as x0 and v0
  • Basic algebraic manipulation skills for solving equations
NEXT STEPS
  • Study the derivation of amplitude in harmonic oscillators
  • Learn about the relationship between angular frequency and amplitude in oscillatory motion
  • Explore the implications of initial conditions on oscillation characteristics
  • Investigate the effects of damping on amplitude in oscillatory systems
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and oscillatory motion, as well as educators seeking to clarify concepts related to harmonic oscillators.

schaefera
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Homework Statement


What value must be equal for two different masses to oscillate with the same amplitude?


Homework Equations


x(t)= Acos(wt+p)
v(t)= -Awsin(wt+p)


The Attempt at a Solution


The answer is (xo)^2+(w*vo)^2

But I really don't understand why... does it have something to do with the fact that, if you subbed into that answer with the x(t) and v(t) equation you would be able to factor out "w" and then the sine and cosine terms squared sum to the value 1?
 
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schaefera said:

Homework Statement


What value must be equal for two different masses to oscillate with the same amplitude?


Homework Equations


x(t)= Acos(wt+p)
v(t)= -Awsin(wt+p)


The Attempt at a Solution


The answer is (xo)^2+(w*vo)^2

But I really don't understand why... does it have something to do with the fact that, if you subbed into that answer with the x(t) and v(t) equation you would be able to factor out "w" and then the sine and cosine terms squared sum to the value 1?

The answer does not seem to be quite right.
I believe it should be: (xo)^2+(vo/w)^2

What you would need, is that A is the same for both masses.
But assuming A, and p are not given, but w and the initial conditions x0, v0 are given, can you solve the equations to find A?
 

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