MHB Making up an Equation That Satisfies Given Conditions

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An equation that satisfies the conditions of having x-intercepts at (-1, 0) and (2, 0) and a y-intercept at (0, 4) can be expressed as y = k(x - 2)(x + 1). To determine the value of k, substitute y = 4 and x = 0 into the equation. This allows for solving k to ensure the equation meets the specified intercepts. The discussion emphasizes the importance of correctly factoring in the y-intercept when forming the equation. Ultimately, the approach leads to a valid quadratic equation that meets all given conditions.
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Make up an equation that satisfies the given conditions: must have x-intercepts at (-1, 0) and (2, 0). It must also have a y-intercept at (0, 4).

Is it correct to say that the equation with x-intercepts would look like this:

y = (x - 2) (x + 1)How do you factor the y-intercept?
 
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Re: Making up an Equation Satisfies Given Conditions

Joystar1977 said:
Make up an equation that satisfies the given conditions: must have x-intercepts at (-1, 0) and (2, 0). It must also have a y-intercept at (0, 4).

Is it correct to say that the equation with x-intercepts would look like this:

y = (x - 2) (x + 1)How do you factor the y-intercept?

You are definitely on the right track. I would use the form:

$$y=k(x-2)(x+1)$$

Now let $y=4$ and $x=0$ and solve for $k$. :D
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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