Water is spilled into a mercury manometer that was being attached to a pipe carrying argon. The water has a height of 20 cm in the manometer and the pressure drop across the manometer is 101.3 kPa (mercury on left lower than on the right) What is the difference in height for the mercury levels on either side of the manometer tube?
General manometer eq: P1+rho1*g*d1=p2+rho2*g*d2+rho(fluid)*g*h
The Attempt at a Solution
I'm really stuck. Does it matter what kind of manometer it is? Can someone help me start this problem out. Thank you so much.