Fluid pressure in a tank - manometer

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Homework Help Overview

The problem involves determining the manometer readings for a fluctuating benzene level in a storage tank, using an open-end manometer. The setup includes a nitrogen blanket at atmospheric pressure and requires consideration of the manometer fluid, either water or mercury, to measure the benzene level accurately.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to relate the pressures at both legs of the manometer, using the equation P=ro*g*h + P(atm), but expresses uncertainty about finding the height of the benzene column in the manometer leg. Participants inquire about the necessary work done and suggest clarifying the problem setup.

Discussion Status

Some participants have noted the need for the original poster to provide more details on their attempts and to follow forum guidelines for posting homework questions. There is an ongoing exploration of the assumptions regarding the manometer fluid and the relationship between the benzene level and manometer readings.

Contextual Notes

The problem lacks specific information about the height of the benzene column in the manometer leg, which is crucial for determining the manometer readings. Additionally, there are reminders about the forum's rules regarding homework help and the importance of showing work done.

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Homework Statement



The level of benzene in a storage tank may fluctuate between 10 cm and 300 cm from the top of the tank. Since it is impossible to see inside the tank, an open-end manometer fluid is to be used to determine the benzene level.
One leg of manometer is attached to the tank at the position of 400 cm from the top. A nitrogen blanket at atmospheric pressure is maintained over the tank contents. (as in image)

What manometer readings R(cm) would be observed at the extremes of the benzene level with water/ mercury as the manometer fluid?
which manometer fluid would you use and why?


Homework Equations



P=ro*g*h + P(atm)

The Attempt at a Solution



the P at both legs of the manometer where the fluid is same level is same so
P(on open end of manometer) = P(atm) + ro (density of water as manometer fluid)*g*R

same for Pressure in the tank (at other end of manometer whith P of benzene in tank) =
P(atm) + ro(Benzene) *g* H (which is height of column of Benzene in tank )

and these two pressures are the same ,
by having H then we can find R . The problem is that I can't figure out how to find H, because we have the manometer 400 cm from top , but it doesn't say about the height of column of benzene on the manometer leg.

Thanks
 

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i need help on this question
 
Angie Aaron said:
i need help on this question
Welcome to PF! :welcome:

Make sure to read the Terms and Rules. We don't typically answer homework questions straight away. We would ask you to show what work you've done on the problem and then try to guide your thinking in the right direction. Also of note, the "Open practice problem" section is a little weird in that it consists of years-old unanswered threads that serve as practice problems for whomever. I can try to ask the mentors to migrate this problem back to the homework section, but you'll probably need to show what work you've done so far on the problem.
 
Angie Aaron said:
i need help on this question
Welcome to the PF. :smile:

Please re-post in the Homework Help, Introductory Physics Homework forum (not the Open Practice Problems forum), and fill out the Homework Help Template you are provided there. This includes sections on the Relevant Equations and your Attempt at a Solution.
 
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