Marianas Trench Homework: Volume & Density Calcs

  • Thread starter Thread starter javacola
  • Start date Start date
javacola
Messages
15
Reaction score
0

Homework Statement


In the Challenger Deep of the Marianas Trench, the depth of seawater is 10.9 km and the pressure is 1.16x10^8 Pa (about 1.15x10^3 atm.

A) If a cubic meter of water is taken from the surface to this depth, what is the change in its volume? (Normal atmospheric pressure is about 1.0x10^5 Pa. Assume that k for seawater is 45.8x10^-11 Pa^-1

B)What is the density of seawater at this depth? (At the surface, seawater has a density of 1.03x10^3 kg/m^3


Homework Equations


DeltaP/K


The Attempt at a Solution


Well for part A I multiplied the K of seawater by the pressure, and got the right answer which is -5.3 x 10^-2 m.
Now I'm kind of stumped on part B. I feel like it's incredibly easy but don't really know where to begin. Obviously m/v=d, but I'm not sure if that's relevant here. Don't know how to relate pressure or depth with density.
 
Physics news on Phys.org
You are given density at the surface, and you calculated how much the volume would change if you moved a certain mass of water down. Keep in mind, that volume of water had a mass, and it did not change. Therefore you have the quantities needed to calculate density.
 
Alright well let's see.

mass divided by initial volume is 1030.
mass divided by initial volume + delta volume = the density I'm looking for.

Is this the right track?
 
My first instant was that since mass is negligent, the change in volume should equal the change in density. But that doesn't seem to be working.
 
javacola said:
Alright well let's see.

mass divided by initial volume is 1030.
mass divided by initial volume + delta volume = the density I'm looking for.

Is this the right track?

Yes. You also know that the initial volume is 1m^3, because that's what the problem says. You can easily find the mass, and from there, the final density.
 
Mass divided by initial volume is 1030. Use this, since you know initial volume, to find mass. Take this mass and divide it by initial volume - delta volume to find the density you are looking for.
 
Thanks a lot guys. Got it with 3 minutes to spare. Have no clue how you knew initial volume was 1, that's what threw me off.
 
javacola said:
Thanks a lot guys. Got it with 3 minutes to spare. Have no clue how you knew initial volume was 1, that's what threw me off.

We know that because the question states:

"If a cubic meter of water is taken..."
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 9 ·
Replies
9
Views
3K
Replies
3
Views
9K
  • · Replies 10 ·
Replies
10
Views
8K
Replies
15
Views
2K
Replies
3
Views
11K
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
Replies
3
Views
2K
  • · Replies 13 ·
Replies
13
Views
11K