Mass Colliding With a Spring (Fixed Speed)

  • Thread starter Thread starter checkmatechamp
  • Start date Start date
  • Tags Tags
    Mass Speed Spring
Click For Summary
SUMMARY

The discussion revolves around calculating the compression of a spring when a 2.77 kg mass, moving at a constant speed of 3 m/s, collides with it. The spring constant is given as 50 N/m. The correct approach involves applying the conservation of energy principle, leading to the equation kx² = mv², which results in a compression of 0.706 meters. The second part of the problem, which involves calculating the time taken for the spring to compress, remains unresolved due to the complexity of the forces involved.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of spring mechanics, specifically Hooke's Law
  • Familiarity with the conservation of energy principle
  • Basic algebra for solving equations
NEXT STEPS
  • Study the application of Hooke's Law in dynamic systems
  • Learn about energy conservation in mechanical systems
  • Explore the relationship between force, mass, and acceleration in collisions
  • Investigate methods for calculating time of compression in spring systems
USEFUL FOR

Students in physics, particularly those studying mechanics, as well as educators and anyone interested in understanding the dynamics of mass-spring systems.

checkmatechamp
Messages
23
Reaction score
0

Homework Statement



A 2.77 kg mass is sliding across a frictional surface. It then encounters a happy little spring, as shown in the figure. By how much will the mass compress the spring? (The mass is moving at 3 meters per second, and the spring constant is equal 50 N/m)

Homework Equations



F = ma
F = kx
F*t = m*v (Possibly?)

The Attempt at a Solution



If the mass was accelerating at 3 m/s^2, the problem would be straightforward. (Just use the acceleration to calculate the force exerted by the mass on the spring, and then divide by the spring constant). But since the mass is moving at a constant speed, you can't do that.

If the speed is constant, acceleration is 0, but that would imply that the spring doesn't compress at all once the mass hits it, which obviously makes no logical sense. I don't think the friction plays any real role (presumably, the mass is traveling at 3 m/s at the instant it hits the spring), and they don't give the coefficient of friction anyway.

The only thing I can think of is if the momentum were calculated, and then divided by the amount of time it takes to compress the spring. But the time isn't given either. (Actually, there's a second part to this question where it asks how long it would take for the spring to compress)

Thanks in advance for your help!
 
Physics news on Phys.org
You didn't attach the figure, but from the question I guess you can assume the spring has no mass, and the other end of the spring is fixed. So conservation of momentum isn't relevant here.

What other types of motion have you studied that involve a mass and a spring?

Or if that doesn't help, what other quantities might be conserved, as well as momentum?

Also did you mean a "frictional surface", or is that a typo for a "frictionless surface"?
 
AlephZero said:
You didn't attach the figure, but from the question I guess you can assume the spring has no mass, and the other end of the spring is fixed. So conservation of momentum isn't relevant here.

What other types of motion have you studied that involve a mass and a spring?

Or if that doesn't help, what other quantities might be conserved, as well as momentum?

Also did you mean a "frictional surface", or is that a typo for a "frictionless surface"?

Yes, the spring has no mass, and the other end is fixed.

I copied and pasted the question, but since he didn't give any coefficient of friction, I'm going to assume he meant frictionless.

The total energy of the system would be conserved. So I tried kx^2 = mv^2, solved for x, and got 0.706 meters (which was the correct answer).

But then I'm not sure what to do for the second part (where I try calculating how long it would take for the spring to compress). I was initially going to use F = kx, solving for F, and then using F*t = m*v to calculate the time it takes to compress the spring, but I tried that, and the program said the answer was wrong.

Then I tried solving for the acceleration (or deceleration, rather), using ma = kx, and then substituting it into the formula x = vit + 0.5at^2, but that didn't work.
 
Last edited:

Similar threads

Replies
17
Views
2K
  • · Replies 5 ·
Replies
5
Views
1K
Replies
29
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
20
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 14 ·
Replies
14
Views
4K
Replies
8
Views
6K