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## Homework Statement

Using a modified version of Kepler's third law and data about Sinope calculate the mass of Jupiter.

Keplers Third Law: p^2=a^3

Newton's Version: p^2=a^3 / M + M

p^2 = a^3/M

M=a^3/p^2

Sinope's period of orbit = 2.075 years

Average orbital distance of Sinope is 0.158 AU

## Homework Equations

Keplers Third Law: p^2=a^3

Newton's Version: p^2=a^3 / M + M

p^2 = a^3/M

M=a^3/p^2

## The Attempt at a Solution

I need Jupiter in solar mass units and then in kg by multiplying it by the mass of the sun (2.00*10^30).

Here is what I have so far but its not making sense.

p=2.075

p^2=4.305625

a^3=4.305625

a=1.62684209

if m=a^3/p^2 and p^2=a^3 I am just going to come up with the same answer of 2.075 which doesn't seem to help me at all. I think the problem is worded bad and I am confused as to where the orbital distance of Sinope comes into play.

Any tips on how to proceed would be appreciated!