Mass of planet expressed as multiple of earth's mass

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The gravitational acceleration on Planet X is 2g, and its diameter is one-third that of Earth's. Using the formula for gravitational force, the mass of Planet X (Mx) can be expressed as Mx = (2/9)Me, where Me is Earth's mass. The calculations confirm that the solution is correct, although there is a recommendation to use proper subscripts in equations for clarity. Proper notation is emphasized as important for understanding. The discussion concludes with an acknowledgment of the formatting issue.
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Homework Statement


On the surface of Planet X, the gravitational acceleration is 2g. If the diameter of Planet X is 1/3 that of Earth's, what is the mass of Planet X, expressed as a multiple of Earth's mass?


Homework Equations


F=G\frac{m1m2}{r^2}


The Attempt at a Solution



let Mx = mass of planet x, Me = mass of earth, Rx = radius of planet x and Re = radius of planet earth. the diameter of planet x is 2Rx and the diameter of Earth is 2Re.
2Rx = \frac{2Re}{3}
Rx = \frac{Re}{3}

we have

a = \frac{GMx}{Rx^2} = \frac{GMx}{(\frac{Re}{3})^2} = \frac{9GMx}{Re^2} = 2g

since 2g = \frac{2GMe}{Re^2} we have

\frac{9GMx}{Re^2} = \frac{2GMe}{Re^2}

GMx = \frac{2GMe}{9}


Mx = \frac{2Me}{9}

Is this correct?
 
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Everything looks fine, I recommend using subscripts with Rx. In LaTeX it is just an underscore followed by the letter:

R_x is R_x.

But the problem you have done correctly.
 
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Agreed. The solution is correct. I also second the need to use subscripts correctly. This kind of thing is more important than what most people realize. Skipping the use of subscripts in an equation is like omitting proper punctuation. People might still understand what you mean, but it's wrong nevertheless.
 
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Ahh ok thanks guys. Sorry about the subscript thing I usually do them when i write it on paper i just didn't know how to do it here.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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