Mass of planet expressed as multiple of earth's mass

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Homework Help Overview

The problem involves determining the mass of Planet X in relation to Earth's mass, given that the gravitational acceleration on Planet X is twice that of Earth's and its diameter is one-third that of Earth. The context is rooted in gravitational physics and the application of Newton's law of universal gravitation.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to derive the mass of Planet X using gravitational equations and relationships between the radii of the two planets. Some participants affirm the correctness of the calculations and suggest improvements in notation, particularly regarding the use of subscripts.

Discussion Status

The discussion appears to be productive, with participants confirming the original poster's calculations and emphasizing the importance of proper notation in mathematical expressions. There is no explicit consensus on further exploration, but the guidance provided seems to enhance clarity in the discussion.

Contextual Notes

Participants note the significance of notation in mathematical communication, indicating a shared understanding of its importance in conveying ideas accurately.

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Homework Statement


On the surface of Planet X, the gravitational acceleration is 2g. If the diameter of Planet X is 1/3 that of Earth's, what is the mass of Planet X, expressed as a multiple of Earth's mass?


Homework Equations


F=G\frac{m1m2}{r^2}


The Attempt at a Solution



let Mx = mass of planet x, Me = mass of earth, Rx = radius of planet x and Re = radius of planet earth. the diameter of planet x is 2Rx and the diameter of Earth is 2Re.
2Rx = \frac{2Re}{3}
Rx = \frac{Re}{3}

we have

a = \frac{GMx}{Rx^2} = \frac{GMx}{(\frac{Re}{3})^2} = \frac{9GMx}{Re^2} = 2g

since 2g = \frac{2GMe}{Re^2} we have

\frac{9GMx}{Re^2} = \frac{2GMe}{Re^2}

GMx = \frac{2GMe}{9}


Mx = \frac{2Me}{9}

Is this correct?
 
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Everything looks fine, I recommend using subscripts with Rx. In LaTeX it is just an underscore followed by the letter:

R_x is R_x.

But the problem you have done correctly.
 
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Agreed. The solution is correct. I also second the need to use subscripts correctly. This kind of thing is more important than what most people realize. Skipping the use of subscripts in an equation is like omitting proper punctuation. People might still understand what you mean, but it's wrong nevertheless.
 
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Ahh ok thanks guys. Sorry about the subscript thing I usually do them when i write it on paper i just didn't know how to do it here.
 

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