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## Main Question or Discussion Point

What would be the mass be of a planet travelling at 500,000 mph - if we assume the planet has the same mass as the Earth i.e. 5.9 sextillion tonnes?

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What would be the mass be of a planet travelling at 500,000 mph - if we assume the planet has the same mass as the Earth i.e. 5.9 sextillion tonnes?

- #2

russ_watters

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I assume you're asking about relativistic effects? That speed is less than 1/1000th the speed of light, so relativist effects can be ignored.What would be the mass be of a planet travelling at 500,000 mph - if we assume the planet has the same mass as the Earth i.e. 5.9 sextillion tonnes?

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The mass of the planet would only change if it was travelling beyond FTL?I assume you're asking about relativistic effects? That speed is less than 1/1000th the speed of light, so relativist effects can be ignored.

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russ_watters

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First a caveat that scientists don't really use the "mass increase" idea anymore. But no, the effects are always there, they are just generally considered negligible until you are moving a substantial fraction of the speed of light (like half).The mass of the planet would only change if it was travelling beyond FTL?

Also, there's no traveling FTL, much less "beyond FTL", whatever that means.....though since this is the science fiction section, I guess it can mean whatever you want.

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- #5

Ibix

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Secondly, relativistic mass (if that turns out to be what you want) is a factor of ##1/\sqrt{1-v^2/c^2}## larger than rest mass. For a speed of half a million miles an hour, about 0.0007c, that is about 1.0000003, about three parts in ten million larger. That's more or less completely negligible.

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Ibix

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Stop it in 1s? Very very high. Stop it in a couple of million years? High. If you're happy to wait long enough, though, you could do it with a bottle rocket, if you could make it sustain thrust long enough.

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Stopping it by catching it, like this:

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Ibix

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Note that he's violating conservation of momentum doing what he's doing, so this number isn't really relevant because physics clearly has nothing to do with this story. Also, a thousand gravities would smash the planet. So there's yet more magic going on here.

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Bandersnatch

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You then have ##F=m\Delta V/\Delta t##

with ΔV = 500,000 mph = 805,000 km/h = 224,000 m/s (assuming by panel 2 the planet has been stopped entirely)

Δt = 10s

m = 6*10E24 kg (like Earth)

which gives F=134*10E27N, so let's round it to F=10E29N for simplicity

Now, it looks like he's trying to stop it with his hands and chest. On average, hands have total surface area of about 0.1 square metres, chest is maybe additional 0.4. Let's say it's twice that because he's a huge buffed-up superhero, so 1 m^2 total. This is where all of that force is concentrated, netting the pressure P=10E29Pa.

This is something like 20 orders of magnitude above the strength of any material in existence (we're assuming here the superdude (Hyperion, is it?) is made of indestructible magical material, but nothing else is).

So if trying to perform such feat, the result would be the hero passing through the planet like a bullet through a balloon.

If he wanted to stop the planet without burrowing into and through it, he'd have to reduce the pressure exerted to something on the order of maybe 10 Mpa, so about 10,000,000 N.

This in turn means that the time between panels 1 and 2, between the 'Hurk!' and 'I... I have it', would have to be extremely compressed, since at that force it'd take in excess of 3 trillion years - longer that the age of the universe.

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Yes, it's Hyperion, he survived the collapse of two universes so it's in keeping with his strength and durability, I guess.

You then have ##F=m\Delta V/\Delta t##

with ΔV = 500,000 mph = 805,000 km/h = 224,000 m/s (assuming by panel 2 the planet has been stopped entirely)

Δt = 10s

m = 6*10E24 kg (like Earth)

which gives F=134*10E27N, so let's round it to F=10E29N for simplicity

Now, it looks like he's trying to stop it with his hands and chest. On average, hands have total surface area of about 0.1 square metres, chest is maybe additional 0.4. Let's say it's twice that because he's a huge buffed-up superhero, so 1 m^2 total. This is where all of that force is concentrated, netting the pressure P=10E29Pa.

This is something like 20 orders of magnitude above the strength of any material in existence (we're assuming here the superdude (Hyperion, is it?) is made of indestructible magical material, but nothing else is).

So if trying to perform such feat, the result would be the hero passing through the planet like a bullet through a balloon.

If he wanted to stop the planet without burrowing into and through it, he'd have to reduce the pressure exerted to something on the order of maybe 10 Mpa, so about 10,000,000 N.

This in turn means that the time between panels 1 and 2, between the 'Hurk!' and 'I... I have it', would have to be extremely compressed, since at that force it'd take in excess of 3 trillion years - longer that the age of the universe.

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Thank you. Yes, comic book physics! The planet was travelling at 500,000 mph, as shown in an earlier panel. I'm wary of posting images on this forum.

Note that he's violating conservation of momentum doing what he's doing, so this number isn't really relevant because physics clearly has nothing to do with this story. Also, a thousand gravities would smash the planet. So there's yet more magic going on here.

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A true superhero is not going to let himself be constrained by the laws of physics!Yes, it's Hyperion, he survived the collapse of two universes so it's in keeping with his strength and durability, I guess.

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Vanadium 50

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Ibix

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The planet rushes onward - but space ITSELF accelerates ahead of it, driven before the MIGHTY forces wielded by this superhero!

(I dunno, but physics has nothing to do with it, so might as well have some fun with it...)

- #16

256bits

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since it's Hyperion. so perhaps he likes to put things in a HYPERbolic orbit ( hence his name! ), so a little bit of a nudge to the left or right would avoid a catastrophic collision, and the compression of time would necessarily be reduced somewhat.'I... I have it', would have to be extremely compressed, since at that force it'd take in excess of 3 trillion years - longer that the age of the universe.

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I have a related question. Taking speed out of the equation, if we assume a planet is stationary, in terms of raw power, how much is required to lift the mass of one planet, if that planet has the same mass as Earth? Superman benched the weight of Earth, Thor lifted a score of planets and Hulk overcame the weight of a star, when I have the calculation showing the power needed to lift one planet, I can then calculate the other two figures.

Yes, I know the physics doesn't work and the planets would be crushed under the weight!

**[mentors’ note - copyrighted images have been removed. If this is a mistake and the images are in fact legally available, PM one of the mentors and we can restore them]**

How Big is the Sun? | Size of the Sun

*The total volume of the sun is 1.4 x 1027 cubic meters. About 1.3 million Earths could fit inside the sun. The mass of the sun is 1.989 x 1030 kilograms, about 333,000 times the mass of the Earth.*

Yes, I know the physics doesn't work and the planets would be crushed under the weight!

How Big is the Sun? | Size of the Sun

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- #18

Vanadium 50

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Then what is the point of this thread?Yes, I know the physics doesn't work and the planets would be crushed under the weight

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The concept of "lifting" something depends on the presence of a large mass (like a planet) with a gravitational field. It then takes energy to lift something, which means move it to a higher potential in the field.I have a related question. Taking speed out of the equation, if we assume a planet is stationary, in terms of raw power, how much is required to lift the mass of one planet, if that planet has the same mass as Earth?

If you are on the Earth, there is no concept of "lifting" the Earth against its own gravity.

If, say, the Moon was sitting on the surface of the Earth, then the force to lift the Moon would depend not only on the Moon's mass, but the mass of the Earth, against whose gravity you are doing the lifting.

If you want to lift the Earth, where are going to put your feet?

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To lift the mass of the Earth above your head, all you have to do is a handstand!This is the Science Fiction and Fantasy Media forum.

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In these feats, they are standing on Earth and taking magic and cosmic power equivalent to the weight of 20 planets and equivalent to the weight of star.If you want to lift the Earth, where are going to put your feet?

- #23

Vanadium 50

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I'm certainly asking what the point is for this thread, where you admit the physics is just made up.. You may as well ask what's the point of any thread in this forum.

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Of course I admit the physics is made up! This is the sci-fi and fantasy forum! The physics in most of the topics here are made up - there's a question about time travel, about Star Wars, compression in Pokeballs etc, etc so why are you asking? Science Fiction and Fantasy take elements from physics but they do not obey the laws of physics, everyone knows this. What do you expect in these forums?!?!I'm certainly asking what the point is for this thread, where you admit the physics is just made up.

Comic books fans have been using physics for decades to determine energy levels or levels of force, for the purpose of debate, to determine the power levels of characters, to determine is A is stronger than B?

- #25

DaveC426913

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"lift" is ambiguous.how much is required to lift the mass of one planet, if that planet has the same mass as Earth?

If you're standing on the Earth, how can you lift it?

Best scenario I can make out of this is if you have two Earth-sized planets in contact, and our hero is standing between them. Now, that means you're dealing with the attraction of

Also, you'll have to hand-wave away the effects of the Roche Limit - which will result in the two planets disintegrating to form a single mass of rubble.

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