1. The problem statement, all variables and given/known data Styrene is a Hydrocarbon. If 0.438g of Styrene is burned in Oxygen and produces 1.481g of CO2 and 0.303g of H20, what is the empirical formula of styrene? 2. Relevant equations 3. The attempt at a solution No. of moles of CO2 - 1.481g / 44.0107g/mol = 0.0337mol No. of moles of C - 0.0337mol No. of moles of H2O - 0.303g / 18.016g/mol = 0.0168mol No. of moles of H - 2 x 0.0168mol = 0.0336mol Mole ratio of C and H - 0.0337 : 0.0336 1 : 1 Is this ratio the empirical formula of Styrene?