Styrene is a Hydrocarbon. If 0.438g of Styrene is burned in Oxygen and produces 1.481g of CO2 and 0.303g of H20, what is the empirical formula of styrene?
The Attempt at a Solution
No. of moles of CO2 - 1.481g / 44.0107g/mol = 0.0337mol
No. of moles of C - 0.0337mol
No. of moles of H2O - 0.303g / 18.016g/mol = 0.0168mol
No. of moles of H - 2 x 0.0168mol = 0.0336mol
Mole ratio of C and H - 0.0337 : 0.0336
1 : 1
Is this ratio the empirical formula of Styrene?