Mass terms in quantum field theory

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Discussion Overview

The discussion revolves around the nature of mass terms in quantum field theory, specifically why these terms are quadratic in fields and do not contain derivatives. Participants explore theoretical foundations and implications related to this characteristic.

Discussion Character

  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant asks why mass terms in quantum field theory are quadratic in fields and not containing derivatives.
  • Another participant suggests that this arises from the process of quantizing a field, where excited states correspond to particles with mass linked to the coefficient of the quadratic term.
  • Another viewpoint connects the quadratic mass terms to the Einstein Mass-Energy Relation, proposing that it is foundational to the structure of quantum field theory.
  • A further elaboration presents a derivation starting from the relationship between energy and momentum, leading to a wave equation and a corresponding Lagrangian that supports the idea that quadratic Lagrangians yield linear equations of motion.
  • One participant humorously notes that the predominance of linear equations in mathematics may explain why the physical world appears linear.

Areas of Agreement / Disagreement

Participants express varying perspectives on the origins and implications of quadratic mass terms, with no consensus reached on a singular explanation or interpretation.

Contextual Notes

Some assumptions regarding the relationship between quantum mechanics and special relativity are implied but not fully explored. The discussion includes various interpretations of foundational principles without resolving the underlying complexities.

voltan
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Does anyone know why in quantum field theory mass terms are quadratic in fields (not contaning derivatives)?

Thanks!
 
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That's just what comes out of quantizing a field. You find that the excited states can be interpreted as particles with a mass corresponding to the coefficient of a quadratic term with no derivatives. I don't know of any good heuristic explanation for this; sometimes you just have to do the calculation and see what comes out.
 
I think that it is determined by Einstein Mass-Energy Relation.
 
Yes - start with Einstein, since QFT is just the quantization of special relativity.

So with c=1, start with E^2 - p^2 = m^2

In terms of 4-momentum this is p^2 = m^2

In quantum theory with h= 1, p -> id/dx where x = (x,t) p = (p,E)

So we get the wave equation, [(d/dx)^2 + m^2] A(x) = 0

The Lagrangian L which produces this when we do DL/DA = 0 is then

L = A(x)[(d/dx)^2 + m^2]A(x)

So in summary we can say: quadratic Lagrangians give linear equations of motion.

At this point you should consider the advice we were given in our undergraduate math course: "the world is Linear because that is the only type of equations mathematicians know how to solve".
 

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