Massless theories can be conformally invariant

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SUMMARY

The discussion centers on the proof that ##P^2##, where ##P_\mu=i\partial_\mu##, is not a Casimir invariant of the Conformal group, leading to the conclusion that only massless theories can be conformally invariant. The participant demonstrated that ##P^2## does not commute with all generators of the conformal group, specifically showing the commutation relations ##[P^2,D]=2iP^2## and ##[P^2,K_\nu]=2i\{P_\nu,D\}+2i\{L_{\mu\nu},P^\mu\}##. This indicates that while ##P^2## is a Casimir operator of the Poincare group, it fails to be so within the context of conformal invariance, necessitating a deeper exploration of mass terms in Lagrangians.

PREREQUISITES
  • Understanding of conformal groups and their generators
  • Familiarity with Casimir operators in quantum field theory
  • Knowledge of commutation relations in operator algebra
  • Basic concepts of mass terms in Lagrangian mechanics
NEXT STEPS
  • Study the properties of Casimir operators in the context of the Poincare group
  • Research the implications of conformal invariance in quantum field theories
  • Explore the role of mass terms in Lagrangian formulations and their invariance under scaling transformations
  • Investigate the physical interpretation of eigenvalues in quantum operators, particularly ##P^2##
USEFUL FOR

The discussion is beneficial for theoretical physicists, particularly those specializing in quantum field theory, conformal field theory, and researchers exploring the implications of massless theories in particle physics.

Joker93
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Homework Statement


The exercise needs us to first show that ##P^2## (with ##P_\mu=i\partial_\mu##) is not a Casimir invariant of the Conformal group. From this, it wants us to deduce that only massless theories could be conformally invariant.

Homework Equations


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The Attempt at a Solution


I have shown that ##P^2## is not a Casimir operator; that is, it does not commute with all the generators of the conformal group. Specifically, I have found that:
##[P^2,D]=2iP^2##
##[P^2,K_\nu]=2i\ \{P_\nu,D\}+2i\{L_{\mu\nu},P^\mu\} ##
and the commutators between ##P^2## and the remaining generators vanish. This shows that ##P^2## is a Casimir operator of the Poincare group (that does not contain ##D## and ##K_\mu##).
Now, for the last part on how this shows us that only massless theories can be conformally invariant, I have no idea on how to show this. It might just be that the lecturer needs a heuristic argument though. We could do it using Lagrangians that contain a mass term and show that the mass term is not invariant under, say, scalings ##x^\mu\rightarrow \alpha x^\mu##, but this way does not follow from the fact that ##P^2## is not a Casimir operator.
 

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Physics news on Phys.org
What is the eigenvalue of P^2? That is - (1) what is the physical interpretation of this eigenvalue, and (2) what value must it take for the conformal algebra to hold?
 

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