Master Converting Metric Units in Scientific Notation: Learn the Simple Method!

  • Thread starter Thread starter Imparcticle
  • Start date Start date
Click For Summary
The discussion revolves around the challenges faced in converting metric units using scientific notation in a conceptual physics class. Initially, the teacher's method of using conversion factors was understood, but a new method involving a chart for unit conversions caused confusion. The student seeks clarification on converting specific problems, particularly from cm² to m² and a conversion involving gigameters. Participants provide hints and corrections regarding the conversion process and exponent rules. Overall, the thread highlights the difficulties in grasping the new method and the need for assistance with metric conversions in scientific notation.
Imparcticle
Messages
572
Reaction score
4
Class started as usual on Tuesday, as my conceptual physics teacher started us on notes on scientific notation. I'm usually good with numbers and having had experience in scientific notation, it was no big deal--at first. Later into our notes, my teacher started doing conversions using sci.not. I still understood it, but not the class. I may have been the only one who got it, and if not one of few in that particular class. Unfortunately, my teacher came back the following day with a whole new method that was supposed to be "simple". It has confused me entirely. So, we have a quiz tomorrow and I don't understand the subject...not a good mix.

Okay, initially he did the problems for conversion by using conversion factors. For example, he would convert mm to nm and then convert to scinot. I totally understood that. BUT, he moved on to conversions involving things like: 10cm2= km2. I figured out how you would do this kind of problem; just do the conversion as though there were no ^2s and after the conversion multiply the exponent by ^2. But apparently I was mistaken because my teacher started working out the problem in a way which I did not understand and eventually stopped and said he would go and figure out a simpler way.

The simpler way is indeed simple: you just use a chart with labled conversion units. So if you are converting m to dm, you count the place values from m to dm and use that for some sort of decimal operation. I don't quite get it.

Anyway, can someone please, please help me with converting metric units in scinot?

here are some conversion problems from my hmwk for example:

10.0 cm2= ___________m2

1.45 x 10[su]9[/sup] = ___________ Gm (I really need help with this one)


thanks
 
Physics news on Phys.org
Here are some hints.
Since 1 cm=10-2 m,
5 cm3= 5 (10-2 m)3 = 5 (10-2)3 m3 = 5 (10-6) m3.
 
10 cm2____________m2

1cm=10-2m
1.00 * 10-4

is that right?

if so, can you help me with the second problem I posted?

thanks
 
If I am not mistaken, 1 cm2 = 10-4m2

So, 10 cm2 = 10 x 10-4m2 = 10-3m2.

I don't think your second question was clear. Was it 1.45 x 109cm or 1.45 x 109m or something else?
 
How do you get -3 as an exponent?
 
101 * 10-4= 10-3

or more generally

am * an= a(m+n)
 
Last edited:
Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

Similar threads

Replies
13
Views
2K
Replies
3
Views
4K
Replies
1
Views
4K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 3 ·
Replies
3
Views
6K
  • · Replies 2 ·
Replies
2
Views
7K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K