Mastering Composite and Inverse Functions: Examples and Explanation

[lionel messi.]

Hi all, can someone please give description about the use of composite and inverse functions with examples...? any help will be appreciated :!)

 

[HallsofIvy]

"Composition of functions" refers to appling to functions in succession. For example, if f(x)= x^3 (whatever x is, cube it) and g(x)= x+ 2 (whatever x is, add 2) then composition g(f(x)) means- what ever x is, first cube it, then add 2. Here, g(f(x))= x^3+ 2. Composition of functions is NOT "commutative"- that is, changing the order may give a different result: g(f(x)), here, means "first add 2 then cube the result: f(g(x))= (x+ 3)^3= x^3+ 9x^2+ 27x+ 27.

Of course, whenever we do an operation, we would like to be able to "undo" it. That is exactly what the "inverse" function does: If we write f^{-1}(x) to mean its inverse function, f^{-1}(f(x))= x and f(f^{-1}(x))= x, With f(x)= x^3, f^{-1}(x)= \sqrt[3](x)= x^{1/3}. That is, the "inverse" of cubing is the cube root. f(f^{-1}(x)= (\sqrt[3](x))^3= x or f(f^{-1}(x))= (x^{1/3})^3= x and f^{-1}(f(x))= \sqrt[3](x^3) or f^{-1}(f(x))= (x^3)^{1/3}= x.

Similarly if g(x)= x+ 3, then g^{-1}(x)= x- 3. That is, the inverse of "add three" is "subtract 3". g(g^{-1}(x))= (x- 3)+ 3= x and g^{-1}(g(x))= (x+ 3)- 3= x.

More generally, we can think of "y= f(x)" as a set of pairs of numbers, f= {(x,y)}= {(x, f(x))}. And then the inverse just swaps "x" and "y"- the pairs corresponding to (y, x): f^{-1}= (y, x)= (y, f^{-1}(y))

You need to be aware that many functions do NOT have inverses! For example, the function f(x)= x^2 does not have an inverse because both f(-2) and f(2) are equal to 4 so there is no single number we can call "f^{-1}(4). What we often do in that case is restrict the domain so the function is "one to one"- but then we have a different function. If we define f(x)= x^2 with x restricted to be non-negative, then we can say that f^{-1}(x)= \sqrt{x}. And if we define g(x)= x^2 with x restricted to be non-positive, then g^{-1}(x)= -\sqrt{x}.

 

[lionel messi.]

Thanks a bunch!