Masters in Physics: Proving Properties of Gamma Matrices

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SUMMARY

This discussion focuses on proving properties of gamma matrices in the context of a master's level physics course. Key properties to prove include the relationship \(\gamma^{\mu+}=\gamma^{0}\gamma^{\mu}\gamma^{0}\), the eigenvalues of the matrices being +/- 1 and +/- i, and the trace of \(\gamma^{\mu}\) being zero. The defining property of the gamma matrices, \(\gamma^\mu \gamma^\nu + \gamma^\nu \gamma^\mu = 2 \eta^{\mu\nu}\), is essential for these proofs, particularly for establishing the eigenvalues and the commutation relations.

PREREQUISITES
  • Understanding of Clifford algebra and its properties
  • Familiarity with gamma matrices and their definitions
  • Knowledge of eigenvalues and eigenvectors in linear algebra
  • Basic concepts of tensor operations in physics
NEXT STEPS
  • Study the properties of Clifford algebra in detail
  • Learn about the representation of gamma matrices in quantum mechanics
  • Explore the implications of eigenvalues in quantum systems
  • Investigate tensor calculus and its applications in physics
USEFUL FOR

This discussion is beneficial for graduate physics students, particularly those studying quantum mechanics and field theory, as well as researchers working with gamma matrices and Clifford algebra.

bubblehead
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I've just started a masters in physics after a 4-year break and am having some real trouble getting back into the swing of things! We have been asked to prove some properties of gamma matrices, namely:

1. \gamma^{\mu+}=\gamma^{0}\gamma^{\mu}\gamma^{0}

2. that the matrices have eigenvalues +/- 1, +/- i

3. The trace of \gamma^{\mu} is zero

4. if \gamma_{5} = -i\gamma^{0}\gamma^{1}\gamma^{2}\gamma^{3} then \gamma_{5},\gamma^{\mu}= 0, \gamma^{2}_{5}=I, eigenvalues = +/- 1


For #1 we are to use the Clifford algebra. We have not been given the definitions of the the gamma matrices -- I don't know if we are expected to know these or if they are irrelevant for the proof. We are also given that gamma 0 is equal to its conjugate transpose and gamma i (i = 1,2,3) is equal to its conjugate transpose times -1. I don't even know where to start on this one -- not quite clear on how the multiplication of the matrices works.

#2 I can do if I take each matrix individually, but how do it do it for the 'general' case of \gamma^{\mu}? By \gamma^{\mu} does it mean I need to take all gammas at once as a set/group/4-vector (how can it be a vector if its components are matricies?), or does it mean for a general gamma mu, where mu = 0,1,2,3?

#3 Same as above, fine if I take each matrix individually, but how to do it generally?

# 4 I can do the eigenvalues and the gamma-five-squared = identity, but I'm not sure about the commutator? Again, do I use some 'general' gamma mu?


I have never had to use tensors before so that whole area is still not quite clear to me -- I understand the concept but not really how tensor operations work.
 
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You will need to use the defining property of the gamma matrices, namely:
\gamma^\mu \gamma^\nu + \gamma^\nu \gamma^\mu = 2 \eta^{\mu\nu}
Most of these should follow from this. For example, this tells you that
(\gamma^0)^2 = 1, (\gamma^i)^2 = -1
What can you conclude about the eigenvalues from this?
 
As they are unitary matrices, it means the eigenvalues are +/- i, +/- 1. Hooray!

I am still stuck on how to show 1.

Using the defining property I can generalize, (\gamma^{\mu})^{2}=\eta^{\mu\mu}. I am given the conjugate transposes for 0 and i, putting those together I get

\gamma^{\mu+}=-\eta^{\mu\mu}\gamma^{\mu}

I can substitute (\gamma^{\mu})^{2} for \eta^{\mu\mu}. For -1 I can substitute the square of gamma zero, giving

\gamma^{\mu+}=\gamma^{\mu}\gamma^{\mu}\gamma^{0}\gamma^{0}\gamma^{\mu}

How do I continue from here? I am stuck on how to rearrange this because the matrices are not commutative. I tried substituting a rearranged defining property for \gamma^{0}\gamma^{\mu} but it didn't seem helpful.
 
Use the anticommutation relation to switch the order of \gamma^0 and \gamma^\mu in \gamma^0\gamma^\mu\gamma^0. It doesn't matter which \gamma^0 you use.
 
Not sure how to do that. Everything I try seems to just cancel back out, e.g.

\gamma^{0}\gamma^{\mu}\gamma^{0} = \gamma^{0}(2\eta^{\mu 0}-\gamma^{0}\gamma^{\mu})

=\gamma^{0}2\eta^{\mu 0}-(\gamma^{0})^{2}\gamma^{\mu}

= \gamma^{0}(\gamma^{\mu}\gamma^{0}+\gamma^{0}\gamma^{\mu})+\gamma^{\mu}

=\gamma^{0}\gamma^{\mu}\gamma^{0}+\gamma^{0})^{2}\gamma^{\mu}+\gamma^{\mu}

=\gamma^{0}\gamma^{\mu}\gamma^{0}

How does this help me?
 
What does the second line evaluate to when \mu=0 and when \mu=i?
 

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