Dirac Trace Algebra: Which Gamma Matrices Matter?

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Homework Help Overview

The discussion revolves around the properties of Dirac's gamma matrices, specifically focusing on the trace of products involving these matrices. The original poster expresses confusion about the significance of the specific gamma matrices in a trace calculation, particularly when dealing with an odd number of matrices.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore whether the specific types of gamma matrices affect the outcome of the trace, questioning the implications of having an odd number of matrices. There is also discussion about the validity of standard trace identities for different gamma matrices.

Discussion Status

Some participants have provided guidance regarding the treatment of gamma matrices with different indices and the implications of having an odd number of them. However, there is no explicit consensus on the broader implications of these observations.

Contextual Notes

There is mention of specific trace identities and the need to treat ##\gamma^5## differently from the other gamma matrices, indicating that certain assumptions about the matrices are under consideration.

Maurice7510
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Homework Statement


This isn't a homework problem; it's just something I'm working on and I'm a little confused as to how to go about dealing with what I have. I have several traces of Dirac's gamma matrices, and I know that the trace of an odd number of gamma matrices is zero. So my first question is: does it matter *which* gamma matrices? For example, one of my traces has
$$ \gamma_{\nu}\gamma^5\gamma^{\rho}\gamma^{\alpha}\gamma^{\sigma}\gamma^0\gamma^5\gamma^0\gamma^{\lambda}\gamma_{\mu}\gamma^{\beta} $$ Since each $$\gamma^5$$ is a product of 4 gamma matrices, altogether this would be a product of 17, which is odd. But some are $$\gamma^{\mu}$$, some $$\gamma^0$$ and some $$\gamma^5$$ and I'm just not sure what the rules are for this type of thing.

Homework Equations


$$Tr (ABC) = Tr (CAB) = Tr (BCA)$$
$$Tr (A +B) = Tr(A)+Tr(B)$$
$$Tr(aA) = aTr(A)$$

The Attempt at a Solution


I would think that this would, in fact, still be zero because there's an odd number of them. Otherwise I would probably use commutation/anticommutation relations to bring the $$gamma^0$$ and $$\gamma^5$$ together (respectively) to get unity, then just deal with the rest.
 
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Maurice7510 said:
zero because there's an odd number of them.
And there is your answer.
 
So does that mean that all the standard trace identies for gamma matrices (e.g. in Griffiths or Peskin Schroeder) hold for *any* gamma matrices, regardless of their index?
 
Maurice7510 said:
*any* gamma matrices, regardless of their index?
As long as that index is 0, 1, 2, or 3. You will need to treat ##\gamma^5## differently.
 
Isn't the last one just a product of the first 4?
 
Maurice7510 said:
Isn't the last one just a product of the first 4?
Yes (up to a factor), so you need to treat it differently.
 

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