Match on water sustained by surface tension

  • #1

Homework Statement


A match of length l=4cm is floating on the surface of the water from a glass. ( the water is at room temperature) If from on one side of the match we pour a few drops of soap, the match starts moving. In which direction is the match mooving and what force is acting upon it? ( sigma (water) = 73 mN/m ; sigma (soap) = 43 mN/m)

Homework Equations


F= sigma * l

The Attempt at a Solution


The force acting on the match is F= (sigma water - sigma soap) * l. I don't fully uderstand how the phenomenon is going on ... could someone draw what's happening in this problem ?

thank you!
 

Answers and Replies

  • #2
Bystander
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  • #3
towards the pure water
 
  • #4
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What causes that?
 

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