Math Help: Multiplying Zeq and I for Transformer - Quick and Easy Tips

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SUMMARY

The discussion focuses on multiplying the complex impedance Zeq with the current I in a transformer context. The impedance Zeq is given as (0.140 + j 0.532), which converts to polar form as 0.550 ∠ 75.26°. The current I is represented as 8.7 ∠ -36.87°. The multiplication results in a product of 4.785 ∠ 38.39°, which can be expressed in rectangular form as 3.75 + j 2.97. This calculation is essential for understanding transformer operations in electrical engineering.

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for transformer , Zeq multiply with I .. let say the Zeq is ( 0.140 + j 0.532 ) , while I is ( 8.7 /_ -36.87 ' ) A ... -36.87 is degree.. how to multiply these two things up? please help me . i m in urgent.. thanks.. please...
 
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yuenkf said:
for transformer , Zeq multiply with I .. let say the Zeq is ( 0.140 + j 0.532 ) , while I is ( 8.7 /_ -36.87 ' ) A ... -36.87 is degree.. how to multiply these two things up? please help me . i m in urgent.. thanks.. please...
Convert Zeq to polar form first.

Since Z = x + j y, the modulus2 = x2 + y2 and the phase angle is the arctan (y / x)

For Zeq = 0.140 + j 0.532,

the modulus2 = 0.1402 + 0.5322 = 0.3026; modulus = 0.550
the phase angle is then arctan (0.532 / 0.140) =arctan (3.80) = 75.26° (1st. quadrant), thus

Zeq = 0.140 + j 0.532 = 0.550 ∠ 75.26°

I = 8.7 ∠ -36.87°

Zeq * I = 0.550 * 8.7 ∠ 75.26° - 36.87° = 4.785 ∠ 38.39° = 3.75 + j 2.97
 
thanks much.. appreciate it...
 

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