Mathematical Representation of a Traveling Wave

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SUMMARY

The discussion focuses on the mathematical representation of a traveling wave described by the equation y = A sin(kx + ωt). Participants analyze the wave's behavior at two specific times: t = 0 and t = T/4, where T is the period of the wave. For t = 0, the wave is represented as y = A sin(kx), indicating motion in the -x direction. At t = T/4, the equation transforms to y = A sin(kx + π/2), suggesting a phase shift of half a wavelength to the left while maintaining the same direction of travel.

PREREQUISITES
  • Understanding of wave equations, specifically y = A sin(kx + ωt)
  • Knowledge of wave parameters: amplitude (A), wave number (k), and angular frequency (ω)
  • Familiarity with the concept of wave period (T) and frequency (f)
  • Ability to graph sine functions and interpret phase shifts
NEXT STEPS
  • Study the properties of sine waves and their graphical representations
  • Learn about wave propagation and directionality in physics
  • Explore phase shifts in wave equations and their effects on graphing
  • Investigate the relationship between frequency, wavelength, and wave speed
USEFUL FOR

Students studying physics, particularly those focusing on wave mechanics, as well as educators seeking to clarify wave behavior and graphing techniques.

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Homework Statement


A wave is represented by y = A sin (kx + ωt). Draw two cycles of the wave from x = 0 to x = 2λ at a) t = 0; b) t = T/4, where T = 1/f = 2∏/ω


Homework Equations


y = A sin (kx+ωt)

k = 2∏/λ (number of wave peaks)


The Attempt at a Solution



I had a really hard time on this problem. From what I could do, for part a, I plugged in t = 0 and from that, I know we would end up with the equation:

y = A sin (kx)

From this, I gathered that the wave would be traveling in a -x direction since the sin function is positive. Outside of that though, I had no idea or understanding how to properly draw it...

Part b, the best I could gather is that in plugging in t = T/4, we'd get an equation of:

y = A sin (kx +ω(T/4)).

In taking T = 2∏/ω

We can find ω and get an equation of:

ω = 2∏/T

So our equation will then look like:

y = A sin (kx + (2∏/T) (T/4))

In simplifying the equation further, we get:

y = A sin (kx +∏/2)

Once again though, I'm lost how to properly draw it. I would really appreciate any guidance on to go about drawing it out. Would this equation also show that the wave is moving in the -x direction?
 
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So I went back to look at this problem again and I think I found what the graph would look like for part a at time zero. I have the document attached. My question for B then, for the equation found for part B, which was:

y = A sin (kx + ∏/2)

does this mean then that the graph would still move in the -x direction but shift by half a wavelength to the left?
 

Attachments

  • Traveling wave at t=0.jpg
    Traveling wave at t=0.jpg
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