Matrix Derivation: 2x1 A and B with Dimension and dA/dB Calculation

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SUMMARY

The discussion focuses on the derivation of the Jacobian matrix for two 2x1 matrices, A and B, defined as A = [f(x) x]^{T} and B = [y x]^{T}. The derivative dA/dB is calculated, resulting in the Jacobian matrix: \(\frac{D(A)}{D(B)}=\left(\begin{array}{cc}0&f^\prime\\0&1\end{array}\right)\). This matrix represents the partial derivatives of the vector-valued function g(y,x)=(f(x),x). The discussion also touches on a separate query regarding the derivative of a square matrix product, indicating the need for further clarification in a new thread.

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tommyhakinen
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Hi,

I need help with matrix derivation. I have 2 matrices of dimension 2x1, A and B.
A = [f(x) x]^{T}
B = [y x]^{T}

I would like to find the dA/dB. How do I do this? and what is the dimension of the resultant matrix?
 
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What is the function that you want to take the derivative of?
 
\frac{D(A)}{D(B)}=\left(\begin{array}{cc}\frac{\partial f(x)}{\partial y}&\frac{\partial f(x)}{\partial x}\\\frac{\partial x}{\partial y}&\frac{\partial x}{\partial x}\end{array}\right)=\left(\begin{array}{cc}0&f^\prime\\0&1\end{array}\right)

This should be it if I'm not mistaken. What you're asking is basically the Jacobian matrix of a vector-valued function g(y,x)=(f(x),x)
 
batboio said:
\frac{D(A)}{D(B)}=\left(\begin{array}{cc}\frac{\partial f(x)}{\partial y}&\frac{\partial f(x)}{\partial x}\\\frac{\partial x}{\partial y}&\frac{\partial x}{\partial x}\end{array}\right)=\left(\begin{array}{cc}0&f^\prime\\0&1\end{array}\right)

This should be it if I'm not mistaken. What you're asking is basically the Jacobian matrix of a vector-valued function g(y,x)=(f(x),x)

thank you very much. that helped a lot.
 
please help me about this quastion :
suppse A be a square matrix and X be a coln matrix AT and XT are their transpos matrices find a formula for this derivative :
d XTATAX/ dA
 
Please create a new thread for your question. And if it is homework, it belongs in the homework forums.
 

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