Solving Matrix Differential Equations: How to Obtain the X Matrix

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SUMMARY

This discussion focuses on solving matrix differential equations to obtain the X matrix from given solutions V1 and V2. The user presents their solutions in exponential form and seeks clarification on how to derive the X matrix and verify the conditions x(0) = I (identity matrix) and dx/dt = AX. The correct formulation of the X matrix is established as X = (v1 v2), where v1 and v2 are defined as vectors. The user ultimately resolves an arithmetic error affecting their calculations.

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zack7
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Homework Statement


The questions are in the image

The Attempt at a Solution


My solutions are
V1=3*(1 -2)e-2t+ (-2) (1 -3)e-3t
V2=1*(1 -2)e-2t+ (-1) (1 -3)e-3t

How do I get the X matrix since my solutions are in exponential still.

Thank you for all the help
 

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Last edited:
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According to your solution,
X=(v_1\ v_2)=\begin{pmatrix}3e^{-2t}-2e^{-3t}&amp;-6e^{-2t}+6e^{-3t}\\<br /> e^{-2t}-e^{-3t}&amp;-2e^{-2t}+3e^{-3t}\end{pmatrix}.
 
Some Pig said:
According to your solution,
X=(v_1\ v_2)=\begin{pmatrix}3e^{-2t}-2e^{-3t}&amp;-6e^{-2t}+6e^{-3t}\\<br /> e^{-2t}-e^{-3t}&amp;-2e^{-2t}+3e^{-3t}\end{pmatrix}.

That means I just plug in t=0 to prove that x(0)=(1 0
0 1) and also use the same method to prove that dx/dt =AX
 
Last edited:
You have the columns and rows swapped.
 
vela said:
You have the columns and rows swapped.

Even after multiplying it I get this respective solutions, what do I do next?
 

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You can write v1 as a single vector:
$$\vec{v}_1 = \begin{pmatrix} 3e^{-2t} - 2e^{-3t} \\ -6e^{-2t} + 6e^{-3t}\end{pmatrix}$$Do the same for ##\vec{v}_2##.
 
vela said:
You can write v1 as a single vector:
$$\vec{v}_1 = \begin{pmatrix} 3e^{-2t} - 2e^{-3t} \\ -6e^{-2t} + 6e^{-3t}\end{pmatrix}$$Do the same for ##\vec{v}_2##.

i get that part but after that what do I do to get just numbers in my 2x2 matrix so that I can prove dx/dt =AX and x(0)= \begin{pmatrix}1 0\\ 0 1\end{pmatrix}
 
Like the problem says, the first column of X is v1. Its second column is v2. It's not going to be just numbers. I'm not sure why you think it has to be.
 
vela said:
Like the problem says, the first column of X is v1. Its second column is v2. It's not going to be just numbers. I'm not sure why you think it has to be.

Okay but then if I put t=0 into the x equation, I do not get the identity matrix and how would I verify that dx/dt=AX by just differentiating the X matrix?.

Thank you for all the help
 
  • #10
Show us how you're calculating X when t=0.
 
  • #11
vela said:
Show us how you're calculating X when t=0.

Okay I got just did a arithmetic error, but how do I verify that dx/dt=AX
 
  • #12
Calculate both sides and show they're equal to each other.
 
  • #13
Okay I will give it a try, thank you very much for all the help.
 

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