Matrix Element of Position Operator

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Homework Help Overview

The discussion revolves around calculating the general matrix element of the position operator in the context of quantum mechanics, specifically within the infinite square well framework. Participants are exploring the mathematical implications of their calculations involving eigenstates and integrals.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to substitute sine eigenfunctions into an integral to compute the matrix element and questions the validity of obtaining a negative result for off-diagonal elements. Other participants discuss the implications of negative results and the relationship to expectation values, as well as the behavior of the momentum operator's matrix representation.

Discussion Status

The discussion is active, with participants providing feedback on the original poster's approach and questioning assumptions about the results. There is an exploration of the implications of integrals yielding zero and the conditions under which this occurs, indicating a productive exchange of ideas without a clear consensus.

Contextual Notes

Participants are navigating the complexities of integrating over specific intervals and the orthogonality of eigenstates, which may affect their calculations and interpretations.

phrygian
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Homework Statement



Calculate the general matrix element of the position operator in the basis of the eigenstates of the infinite square well.

Homework Equations



[tex]|\psi\rangle =\sqrt{\frac{2}{a}}\sin{\frac{n \pi x}{a}}[/tex]

[tex]x_{n,m}=\langle\psi_{n}|\hat{x}|\psi_{m}\rangle=\int^a_0\psi^\star_{n} x \psi_mdx[/tex]

The Attempt at a Solution



What I tried doing is substituting the sin eigenfections into the integral and then using the relation that sin(x)sin(y)=(cos(x-y)-cos(x+y))/2 and then integrating from 0 to a. I keep getting a negative answer, am I using the wrong approach? I know this doesn't work when m=n, but shouldn't it work when they aren't equal?

Thanks for the help
 
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Sounds like you're doing it right. Why do you think a negative answer for the off-diagonal elements is wrong?
 
I guess I was thinking of it as an expectation value which I now see is not correct.

When use this same method using the momentum operator, -i hbar d/dx, I get an integral with Sin(npix/a)Cos(npix/a), which must be zero when integrated from 0 to a by integral identities, correct? What does this mean then if the momentum operator is represented by a matrix with all zeros?
 
No, it won't be all zeros. Remember you're not always integrating over a full period (depending on what m and n equal), so you can't use orthogonality to say the integrals will all be zero.
 

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