- #1

princessfrost

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**A 0.150-kg frame, when suspended from a coil spring, stretches the spring 0.050 m. A 0.200-kg lump of putty is dropped from rest onto the frame from a height of 30.0 cm.**

Find the maximum distance the frame moves downward from its initial position in meters.

Find the maximum distance the frame moves downward from its initial position in meters.

First I found the spring constant, k, which is given by F = -kx.

F = -kx

k = -F/x = -(0.150kg *9.8 m/s2)/(0.050m) = 29.4 N/m

Next, I found the force that the lump of putty makes on the frame. The force is given by F = ma. The mass of the putty, 0.200kg, and the acceleration which is due to gravity, -9.8m/s2.

F = ma = 0.200kg * -9.8m/s2 = 1.96 N

Now the spring constant, k (29.4N/m), and the force of the putty, 1.96N, so I finally solve for the distance the frame moves.

F = -kx

x = -k/F = -(29.4N/m)/(1.96N) = -15m

It is negative, because it moves in the -x direction.

So, the frame moves 15m downwards is what I get but my program says it is wrong. Can someone please help me?