Maximum extension of system with two blocks connected by a spring

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Homework Help Overview

The problem involves two blocks of masses connected by a spring, subjected to a constant force. The original poster seeks to determine the maximum elongation of the spring and the distances moved by the blocks.

Discussion Character

  • Conceptual clarification, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of conservation of mechanical energy and the conditions for static equilibrium. Questions arise regarding the relationship between net force, work done, and mechanical energy conservation.

Discussion Status

The discussion is exploring various interpretations of the problem, particularly the distinction between maximum extension and static equilibrium. Some participants provide guidance on using Hooke's Law and conservation of momentum, while others challenge assumptions about net forces and work done.

Contextual Notes

There is confusion regarding the definitions of static equilibrium and maximum extension, as well as the implications of net forces and work done on the system's mechanical energy.

carlyn medona

Homework Statement


Two blocks of masses m, and m2 are connected by a
spring of spring constant k.
Suppose each of the blocks is pulled by a constant force F
Find the maximum elongation spring will suffer and the distances moved by the two

Homework Equations

The Attempt at a Solution


the two forces are acting on opposite direction. so net force on the system is zero. So I applied conservation of mechanical energy. Initial and final kinetic energy is zero. and final spring potential energy is kx^2/2. this doesn't make sense to me.
 
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carlyn medona said:
this doesn't make sense to me.
Why not, and if it does not make sense to you, why did you do it?
 
We need to calculate the final extension ##x## of the spring. For the final system to be static, the spring tension must be ##F## to exactly cancel the applied force. Given that, what is ##x## (use Hooke's Law)?

To calculate the motion of each block, we can use conservation of momentum. Since the external forces are equal and opposite at all times, the combined momentum of the two blocks must remain constant. What does that tell us about the ratio of the distance traveled by m to that traveled by m2?
 
andrewkirk said:
We need to calculate the final extension x
No, we are asked for the maximum extension. It will not be static.
The OP method is correct, and very neat, though lacking a few justifying details.
 
andrewkirk said:
We need to calculate the final extension ##x## of the spring. For the final system to be static, the spring tension must be ##F## to exactly cancel the applied force. Given that, what is ##x## (use Hooke's Law)?

Sorry , this is incorrect . Maximum extension is not a state of equilibrium . At maximum extension , spring force is greater than the applied constant force .
 
If net force on my system is zero. Wont net work be zero. that means total mechanical energy is conserved. Initially it is zero and final is kx^2/2. Why?.Is net on the system not zero? I am so confused.
 
carlyn medona said:
If net force on my system is zero. Wont net work be zero
No. The forces are opposite, but so are the displacements. The work done is positive in each case.
 
carlyn medona said:
net force on my system is zero. Wont net work be zero

Not in this case .

carlyn medona said:
that means total mechanical energy is conserved.

Total mechanical energy is conserved only when total work done by non conservative forces is zero .

Total work done on an object could be zero , yet total mechanical energy may not be conserved .
carlyn medona said:
Is net on the system not zero?

Go by the definition of Work done by a force .Consider each force separately . What is the direction of force on anyone block ? What is the direction of displacement of that block ? Is it positive or negative ?

Now what is the net work done by the two forces ?
 
okay, Now it does make sense. Thanks a lot.
 

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