Max distance of rectangle that electron beam can pass through

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Homework Help Overview

The problem involves a beam of electrons moving through a rectangular region with a uniform magnetic field directed in the -z direction. The challenge is to determine the maximum width, d, of the rectangular region that allows the electron beam to pass through without turning back.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between the radius of the circular motion of electrons in a magnetic field and the width of the rectangular region. There is mention of relevant equations such as F=qvB and a=v²/r, as well as the concept that if the radius is smaller than d, the electrons will not exit the region.

Discussion Status

Some participants are exploring the implications of the radius of the electron's path in relation to the width of the rectangular region. There is an ongoing inquiry into how to relate distance to the equations provided, with hints being sought for further understanding.

Contextual Notes

One participant notes difficulty in connecting distance to the problem, indicating a potential gap in the information or understanding of how distance factors into the equations at play.

kkcolwell
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Homework Statement



A beam of electrons is fired into a rectangular region of space that contains a uniform magnetic field in the -z direction. The electrons are moving in the +x direction, as shown. The speed of the electrons in the beam is 6.00 × 106 m/s. The mass of an electron is me = 9.11 × 10−31 kg. The magnitude of the magnetic field in the rectangular region of space is 1.50 × 10−2 T. The rectangular region has a width d.


What is the maximum value of d for which the electron beam will make it through to the other side of this rectangular region, and continue on to the right of the region?


Homework Equations



|⃗v|=|E⃗|/|B⃗1|

(Equations provided)
|F⃗m| = |q||⃗v||B⃗ || sin(θ)|
|F⃗m| = IL|B⃗ || sin θ| r = m | ⃗v |
|q||B⃗ | r = m | ⃗v ⊥ | |q||B⃗ |
|F⃗E|=|F⃗B| −→ q|E⃗|=q|⃗v||B⃗1| −→ |⃗v|=|E⃗|/|B⃗1| | m⃗ | = N I A
τ = NIA|B⃗||sinθ| = |m⃗ ||B⃗||sinθ|
| B⃗ | = μ 0 I 2πr
| B⃗ | = μ 0 N I 2r
| B⃗ | = μ 0 N I L
Φv =|⃗v|Acos(θ)
ΦB =|B⃗|Acos(θ)
E = N|∆Φ| ∆t
I = V/R
I = E/R (linear DC generator)
E = BvL (linear DC generator)
I = E/R = BvL/R (linear DC generator)
Fm = ILB = (B2vL2)/R (linear DC generator)
Pmechanical = Fappl v Pelectrical = IV = IE
ΦB = BA cos(ωt) (rotary AC generator)
E = (NBAω)sin(ωt) (rotary AC generator)
I = E/R = (NBAω/R) sin(ωt) 1Tesla(1T)=1 N
μ0 =4π×10−7 Tm A



The Attempt at a Solution



E=6.00 x 10^6m/s x 1.50 x 10^-2 T
90000 T x m/s

Ok the problem I am having is relating distance to any equation I have. In previous problems I have worked, none of them had distance as part of the problem. If someone could just give me a hint or something about how to relate distance to the problem, that would be much appreciated.
 

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Magnetic fields make moving charged particles move in circles. If the radius of the circle is too small, the electrons will remain in the region.
The relevant equations are F=qvB and a=v2/r, and of course, F=ma
 
I attached a picture to go along with my problem, did you happen to look at it? I am not sure if I attached it right.
 
The picture clarified it a bit, but nothing has changed.
The electrons will follow a circle with radius r. If r is smaller than d, then the electrons will turn around and come back the way they came.
 

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