Max EMF in a Model AC Generator Coil

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SUMMARY

The maximum electromotive force (emf) induced in a model AC generator with a 500-turn rectangular coil measuring 8.0 cm by 20 cm, rotating at 120 revolutions per minute in a magnetic field of 0.60 T, is calculated to be 60.28 V using the formula εmax = NBAω. The instantaneous emf at t = (π/32) seconds is determined to be 56.87 V. The smallest value of t for maximum emf occurs at t = 0.125 seconds, derived from the condition ωt = π/2, where the sine function reaches its peak value of 1.

PREREQUISITES
  • Understanding of electromagnetic induction principles
  • Familiarity with the formula for maximum emf: εmax = NBAω
  • Knowledge of trigonometric functions, specifically sine
  • Ability to convert between revolutions per minute and radians per second
NEXT STEPS
  • Study the derivation and applications of the formula ε = εmax sin(ωt)
  • Learn about the relationship between angular frequency and linear motion in AC generators
  • Explore the significance of phase angles in sinusoidal functions
  • Investigate other scenarios of electromagnetic induction, such as varying magnetic fields
USEFUL FOR

Students preparing for physics exams, educators teaching electromagnetic theory, and anyone interested in understanding the principles of AC generators and electromagnetic induction.

mydoghenry
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Homework Statement


In a model ac generator, a 500 turn rectangular coil, 8.0 cm by 20 cm, rotates at 120 rev/min in a uniform magnetic field of 0.60 T.

(a) What is the maximum emf induced in the coil?
(b) What is the instantaneous value of the emf in the coil at t = (∏/32)s? Assume that the emf is zero at t = 0.
(c) What is the smallest value of t for which the emf will have its maximum value?

Homework Equations


εmax=NBAω
ε=εmaxsinωt

The Attempt at a Solution


I easily understand part a and b (below):
(a)
Area=0.08x0.20=0.016 m2
120rev/min = 12.56 rad/s

εmax=NBAω
εmax=500(0.60)(0.016)ω
εmax=60.28V

(b)
ε=εmaxsinωt
ε=60.28sin(12.56∏/32)
ε=56.87V

(c)
Part c is where I am totally confused. We did this problem in class, so I will show you what my teacher came up with and explain why I don't understand.

ε=εmaxsinωt
ωt=∏/2 --> ε=εmax
12.56t=∏/2
t=∏/2(12.56)=0.125 s

I do not understand where/how my teacher came up with ωt=∏/2. Why are we dividing pi by 2? And how do we know this is equal to ωt? Are we just supposed to know this equation? Is it a common physics rule? I want to know the "why" behind it and not just memorize that equation so I can apply it to other situations. For instance, what if we're asked what the largest value of t for which the emf will have it's maximum value?" Then it wouldn't still be pi over 2?

I have a test Thursday and have been wracking my brain trying to figure out why or how he came up with part c. I would greatly appreciate any and all help. Thank you so much! :!)
 
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welcome to pf!

hi mydoghenry! :smile:
mydoghenry said:
ε=εmaxsinωt
ωt=∏/2 --> ε=εmaxsinωt

I do not understand where/how my teacher came up with ωt=∏/2.

the maximum value of sin (= 1) is when the angle is π/2 :wink:
 


Thank you so very, very much. It makes sense now. I must have missed the day in class when we learned ∏/2 is the radian form of 90°.

Do you think there's any other way for that question to be asked? For instance, What is the smallest value of t for which the emf will have its minimum value? In this case would it be sin180 (aka sin∏) which I guess is zero. So, maybe there's only one way he'd ask this question.
 
mydoghenry said:
So, maybe there's only one way he'd ask this question.

yes …

he's really not trying to trick you! :smile:
 

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