Max Height of Rocket A Above Earth's Surface

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SUMMARY

The maximum height H of a rocket launched from Earth's surface with a mass of 1.20 x 103 kg and an initial speed of 7.00 km/s is calculated using gravitational potential energy and kinetic energy conservation principles. The correct formula to use is (1/2)mv02 - (GMm)/Re = -(GMm)/(H + Re), where G is the gravitational constant and Re is Earth's radius. The calculated maximum height is 4.08 x 106 meters above the Earth's surface, confirming the importance of correctly applying distance in potential energy calculations.

PREREQUISITES
  • Understanding of gravitational potential energy and kinetic energy concepts
  • Familiarity with the gravitational constant (G) and Earth's radius (Re)
  • Knowledge of energy conservation principles in physics
  • Basic algebra for solving equations involving variables
NEXT STEPS
  • Study gravitational potential energy calculations in varying distances from Earth
  • Learn about the conservation of energy in rocket physics
  • Explore the implications of mass and velocity on maximum height in projectile motion
  • Investigate the effects of varying gravitational acceleration on objects at different altitudes
USEFUL FOR

Physics students, aerospace engineers, and anyone interested in the principles of rocket motion and energy conservation in gravitational fields.

eurekameh
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A rocket of mass m=1.20x10^3 kg is launched vertically upward from the Earth's surface with an initial speed v0 = 7.00 km/s.
Calculate the maximum height H of point A above the Earth's surface at which the rocket will momentarily come to rest, before it starts falling back on the earth.

So I know energy (kinetic and potential) is conserved? I've tried using E(initial) = E(final) --> (1/2)mv0^2 = mgh, but figured this wouldn't work because g is not 9.8 m/s^2 far from the earth. Instead, I used (1/2)mv0^2 - (GMm)/Re = -(GMm)/H. I solved for H, but it did not give me the correct solution, which is 4.08 x 10^6. Can anyone help me out?
 
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Check your use of distance in the potential energy terms.
 
Filip Larsen said:
Check your use of distance in the potential energy terms.

I'm supposed to use (1/2)mv0^2 - (GMm)/Re = -(GMm)/(H+Re), aren't I? Lol. Thanks!
 

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