A man has 340 yds of fencing for enclosing two separate fields, one of which is to be rectangular twice as long as it is wide and the other a square. The square field must contain at least 100 sq. yds. And the rectangular one must contain at least 800 sq. yds. Find the maximum and the minimum values of the width x of the rectangular field. What is the greatest number of square yards that can be enclosed in the two fields? What I have so far: (not too much) A= bh One rectangle is bh (area 100 sq. yards or more), the other us 2b x 2h (area 800 sq. yards or more). bh+ (2b)(2h) = 340 (???) I am really having trouble coming up with an equation and solving the problem in general. Any help would be greatly appreciated.