- #1

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## Homework Statement

I derived this problem from back when I used to play Evony. I do not endorse this game whatsoever, and I think it has made enough of a mockery for itself with its plentiful supply of false and explicit advertisements such that I don't need to add to its shame.

Anyway, my problem was that I wanted to figure out a means to achieving maximum income through the game's population-tax policy. This is how it works:

You build houses to make room for your population. The more houses, the higher your maximum population potential (denoted P) will be. The actual population you can have will be between 0 and P. This population is dependant on the tax rate (denoted T), and it follows a simple inversely proportional function. With 100% T, you will have 0 population. With 0% T you will have P population. Of course, in both these cases you will have a 0 income so they are the extreme minimums. At, say, 50% T, you will have P/2 population so you will then make P/4 gold/hour (each population gives 1 gold/hour when taxed at 100%, so 2 people give 1 gold/hour at 50% T).

## The Attempt at a Solution

The people, x, is defined by: [tex]x=P\left(\frac{T}{100}\right)[/tex] where [itex]0\leq T\leq 100[/itex]

The income, I, is defined by: [tex]I=x\left(\frac{T}{100}\right)[/tex]

Therefore by combining both equations we get: [tex]I=\frac{PT^2}{100^2}[/tex]

Now, P is a constant since the max pop is defined and not going to change (for this calculation at least) and I want to find the ideal tax rate, T, in order to get maximum income.

If I take: [tex]\frac{dI}{dT}=2.10^{-4}PT=0[/tex]

I get [itex]T=0[/itex] since [itex]P\neq 0[/itex]

So what am I doing wrong? Since I already established that the extremities of the tax rate, [itex]T=0,100[/itex] result in 0 income.

And if you don't understand or need clarification in something, don't hesitate to ask

Thanks for helping me satisfy my curiosity.