Maximum Acceleration for Flatbed Truck with Jet-Powered Crate

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Homework Help Overview

The problem involves a jet-powered flatbed truck with a crate, focusing on determining the maximum acceleration without the crate sliding. The context includes forces acting on the crate, such as tension, friction, and gravity, with specific coefficients of static and kinetic friction provided.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to analyze the forces acting on the crate, including friction and tension, but expresses uncertainty about identifying the opposing horizontal force. Some participants suggest starting with a Free Body Diagram to clarify the forces involved.

Discussion Status

The discussion is ongoing, with participants exploring the setup of the problem and clarifying terminology. Guidance has been offered regarding the importance of visualizing forces through a Free Body Diagram, but no consensus or resolution has been reached yet.

Contextual Notes

Participants have noted the need for clearer definitions of symbols used in the equations and the relationships between the forces acting on the crate. There is an indication of confusion regarding the opposing force to friction that needs to be identified.

Antendo.
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Homework Statement



A jet-powered flatbed truck has a crate of mass m, which is strapped down to the truck with a tension three times the weight of the box. Find the maximum acceleration without having the box slide. Us= .9, Uk=.7

Homework Equations



Fun= SUM
Fun= ma
Ff= -(Us) Fn


The Attempt at a Solution



I've figured out the Y components, and resulted in the Ff= 35.3m, my only problem now is where to go from here. I can't for the life of me figure out the other horizontal force other than Ff.

when I attempt the solution, I get

Fun=SUM
= Ff
=35.3m

Fun=ma
35.3m=ma
35.3=a

I know the answer is -7.7 but I can't seem to think of the opposing horizontal force.
 
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You need to start off with a Free Body Diagram for the crate.

By the way, what is SUM? Fun? Ff? It would really help to put some words with these symbols.
 
I apologize, SUM is the sum of all the forces, and Fun is the unbalanced force, in this case it would be force of friction (Ff) and something else. Also Fn is the normal force, and Fg is the force of gravity, and Fa would be an applied force.

My free body diagram includes the box with the force of gravity, and tension acting downward, and force normal pushing it up. Horizontally it has the force of friction resisting the box's movement, but I don't know what it's opposing :(
 
bump.
 

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