Maximum energy stored in the capacitor = 0.85 Joules

In summary, the maximum energy stored in a capacitor is calculated using the formula E = 1/2 * C * V^2, with units of Joules (J). It can be greater than 0.85 Joules depending on the capacitance and voltage values. The maximum energy stored affects the capacitor's performance by determining its charge holding and work capabilities. Factors such as capacitance, voltage, dielectric material, temperature, and aging can all affect the maximum energy stored in a capacitor.
  • #1
SoulofLoneWlf
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0

Homework Statement


An L-C circuit has an inductance of 0.430 and a capacitance of 0.240 . During the current oscillations, the maximum current in the inductor is 1.40 .

What is the maximum energy stored in the capacitor at any time during the current oscillations?
Express your answer in joules.


Homework Equations


v=ir
e=ir ideal
1/2LI^2 +1/2CV^2 = Constant


The Attempt at a Solution



1/2LI^2 +1/2CV^2 = Constant
allowing v to be i in ideal zero resistance tho not stated ><
 
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  • #2
sorry about that folks had a brain fart was using nf instead of H :)
 
  • #3


1/2(0.430)(1.40)^2 +1/2(0.240)(1.40)^2 = Constant
0.833 Joules

I would like to clarify the units of inductance and capacitance in the given information. Assuming the inductance is in henries (H) and the capacitance is in farads (F), the maximum energy stored in the capacitor can be calculated using the formula E=1/2*CV^2, where C is the capacitance and V is the maximum voltage across the capacitor.

Using the given values, the maximum voltage across the capacitor can be calculated as V=IL= (1.40 A)(0.430 H) = 0.602 V.

Substituting this value into the energy formula, we get E= 1/2*(0.240 F)*(0.602 V)^2 = 0.0432 J.

Therefore, the maximum energy stored in the capacitor during the current oscillations is approximately 0.0432 joules. It is important to note that this is a theoretical maximum and in practice, there may be losses in the circuit that reduce the actual energy stored in the capacitor.
 

1. How is the maximum energy stored in a capacitor calculated?

The maximum energy stored in a capacitor is calculated using the formula E = 1/2 * C * V^2, where E is the energy in Joules, C is the capacitance in Farads, and V is the voltage across the capacitor in Volts.

2. What is the unit of measurement for maximum energy stored in a capacitor?

The unit of measurement for maximum energy stored in a capacitor is Joules (J).

3. Can the maximum energy stored in a capacitor be greater than 0.85 Joules?

Yes, the maximum energy stored in a capacitor can be greater than 0.85 Joules. It depends on the capacitance and voltage values used in the calculation.

4. How does the maximum energy stored in a capacitor affect its performance?

The maximum energy stored in a capacitor affects its performance by determining the amount of charge it can hold and the amount of work it can do. A higher maximum energy storage allows the capacitor to hold more charge and perform more work.

5. What factors can affect the maximum energy stored in a capacitor?

The maximum energy stored in a capacitor can be affected by the capacitance value, the voltage applied, and the type of dielectric material used in the capacitor. Temperature and aging can also affect the maximum energy stored in a capacitor.

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