Maximum speed before Rope Breaks

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proness26
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Homework Statement


A mass of m is placed on the end of a rope of length l and swung in a vertical plane. The rope can withstand a maximum tension of P N(Newtons), after which it breaks. What is the maximum uniform speed that the object can be swung at, before the rope breaks?

Homework Equations



T-Fg=m(V^2/R)

The Attempt at a Solution



At which point on the vertical plane would I check to get maximum uniform speed?
Would I check the top where both Fg and T will be accelerating the object towards the center of the circle? Or would I check the bottom where T and Fg will be acting in opposite directions?
 
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proness26 said:

Homework Statement


A mass of m is placed on the end of a rope of length l and swung in a vertical plane. The rope can withstand a maximum tension of P N(Newtons), after which it breaks. What is the maximum uniform speed that the object can be swung at, before the rope breaks?

Homework Equations



T-Fg=m(V^2/R)

The Attempt at a Solution



At which point on the vertical plane would I check to get maximum uniform speed?
Would I check the top where both Fg and T will be accelerating the object towards the center of the circle? Or would I check the bottom where T and Fg will be acting in opposite directions?

Well, at which of these two situations would the tension be larger? The rope must not break at any point in the cycle, which means it must be able to withstand the largest tensile force that it will be subjected to.
 
Ohh ok I got it then. Bottom. Seems like a silly question now that I look at it haha