Maximum Velocity= 4.8 m/s2Deceleration= -1.2m/s2

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SUMMARY

The maximum velocity of the lift is calculated to be 4.8 m/s after accelerating from rest at 1.2 m/s² for 4 seconds. The lift then travels at this constant velocity for 8 seconds before decelerating to rest over a period of 3 seconds. The deceleration during this final phase is determined to be -1.6 m/s². These calculations utilize the kinematic equation v = u + at, where u is the initial velocity, a is the acceleration, and t is the time.

PREREQUISITES
  • Kinematic equations, specifically v = u + at
  • Understanding of acceleration and deceleration concepts
  • Basic algebra for solving equations
  • Knowledge of units for velocity (m/s) and acceleration (m/s²)
NEXT STEPS
  • Study the application of kinematic equations in different motion scenarios
  • Learn how to derive acceleration and deceleration from velocity-time graphs
  • Explore real-world applications of lift mechanics and safety protocols
  • Investigate the effects of varying acceleration rates on passenger comfort
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Students studying physics, engineers involved in lift design, and anyone interested in understanding motion dynamics in mechanical systems.

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m/s2
 

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