(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A man stands on the roof of a building of height 16.6 and throws a rock with a velocity of magnitude 25.0 at an angle of 35.0 above the horizontal. You can ignore air resistance.

Calculate the magnitude of the velocity of the rock just before it strikes the ground.

2. Relevant equations

y - y_{0}= v_{0y}^{2}+ 1/2 a_{y}t^{2}

v_{y}^{2}= v_{0}^{2}+ 2a_{y}(y - y_{0})

3. The attempt at a solution

I calculated that the projectile would go 10.5 meters above the building which would make the total height of 27.1m. I also calculated how much time it would be in the air - 3.74s - and then found the range - 76.6m (I didnt do all that for fun, it was to answer other parts of this question). I figured using the second equation I listed would give me the velocity of the y component.

I get v_{y}= 23m/s and then divided by sin(35) to get the velocity

???

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# Homework Help: Maximum Velocity in projectiles

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