Maximum Voltage without causing Dielectric Breakdown?

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To achieve a capacitance of 24 pF with an air-filled, parallel-plate capacitor and a plate separation of 2.3 mm, a plate area of 6.2 x 10^-3 m^2 is required. The maximum voltage that can be applied without causing dielectric breakdown is calculated using the critical electric field in air, which is approximately 3 x 10^6 V/m. By applying the formula E = V/d, the voltage is determined to be 6900 Volts, which should be rounded to 7 kV to reflect the significant figures of the critical field value. The discussion highlights the importance of proper significant figure usage in calculations. Understanding these concepts is essential for accurate electrical engineering applications.
mli273
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1. What plate area is required if an air-filled, parallel-plate capacitor with a plate separation of 2.3 mm is to have a capacitance of 24 pF?

Which I found correctly to be 6.2 x 10^-3 m^2 by using the formula C= k(8.85x10^-12)A/d

What is the maximum voltage that can be applied to this capacitor without causing dielectric breakdown?


2. I know V=Q/C, and that I have C, but I'm not sure what to substitute for Q, or if I need another formula completely. Help?
 
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You should know the value for the critical electric field Ec in air (the electric field that would cause electric breakdown) and calculate the voltage from the formula:

<br /> E = V/d<br />
 
3x10^6= V/.0023, so V = 6900 Volts. Thank you, I always have trouble on the simple ones.
 
You have too many significant figures in your end result, by the way. Because you stated the value of the critical field with one significant figure only, it means you should state your maximum voltage with that many significant figures. This should lead to a value of 7 kV.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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