Me solving 2 electrical network problems

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SUMMARY

This discussion focuses on solving two electrical network problems using Thevenin's theorem. In the first problem, the user calculated the Thevenin voltage (Vth) as 14.28V and Thevenin resistance (Rth) as 1.1428Ω, leading to a current through a 5Ω resistor of 2.34A, which contradicts the expected answer of 4A. In the second problem, the user derived the Thevenin voltage (Vth) as 15V and calculated the short-circuit current (Isc) as 0.48A, resulting in a current through a 24Ω resistor of 0.271A. The user seeks confirmation of their calculations.

PREREQUISITES
  • Understanding of Thevenin's theorem
  • Knowledge of Kirchhoff's Current Law (KCL)
  • Familiarity with Kirchhoff's Voltage Law (KVL)
  • Basic circuit analysis techniques
NEXT STEPS
  • Review Thevenin's theorem applications in circuit analysis
  • Practice problems involving KCL and KVL
  • Explore dependent sources in electrical circuits
  • Learn about circuit simulation tools like LTspice for verification
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in analyzing electrical networks will benefit from this discussion.

pforpashya
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please help me solving 2 electrical network problems

file:///C:/Documents%20and%20Settings/user/My%20Documents/My%20Pictures/From%20RSPC_Pashya/Camera%20roll/WP_000127.jpg

In first problem I have to find current through 5Ω resistor using Thevinins eq.

So, in first step i removed 5Ω resistor with open ckt. hence Ix=0 hence the dependent source becomes zero. 4A+1A that is 5A going up. then kcl at above node yields me node voltage 14.28v

so my vth comes 14.28v

now, as Ix becoming zero and dependent source becoming zero we can calculate Rth=1.1428Ω
so to find current thru 5Ω

I will be 14.28/6.1428... hence i got answer as 2.34A.

But answer given to me is 4A.

please help.

In second problem also we need to find current through 24Ω using Thevinins eq.

I applied kvl at input side & kcl at output side got two equations
8Ix-Vx=16
130Ix+Vx=0

solving i got Vx=15v == Vth

then solved for Isc which i got 0.48A
Current throgh 24 ohm i got 0.271A

am i correct?

please help
 
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welcome to pf!

hi pforpashya! welcome to pf! :smile:
pforpashya said:
file:///C:/Documents%20and%20Settings/user/My%20Documents/My%20Pictures/From%20RSPC_Pashya/Camera%20roll/WP_000127.jpg

erm :redface: …

i can't see the picture …

it's still on your computer! :wink:​
 

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