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Of course you have to distinguish the symbols. I'm an advocate of the good old Ricci calculus, because there it's much more intuitive. What I used, however in my previous postings in this thread is Cartan calculus on manifolds for the special case of holonomous coordinates. There the symbol ##\mathrm{d} q^{\mu}## is a tangent-space dual vector, i.e., a one-form, i.e., a linear mapping from tangent space at a point on the manifold, parametrized with real generalized coordinates ##q^{\mu}##. The holonomous tangent-space basis at the point defined by the tangent vectors of the coordinate lines, i.e., keeping all ##q^{\mu}## constant except one. This basis is denoted by ##\partial_{\mu}##. By definition the dual basis ##\mathrm{d} q^{\mu}## maps these holonomous basis vectors as follows ##\mathrm{d} q^{\mu}(\partial_{\nu})={\delta^{\mu}}_{\nu}##, where the latter symbol is the usual Kronecker ##\delta##.
In the Ricci calculus the ##\mathrm{d} q^{\mu}## are simply infinitesimal increments of the coordinates and thus
$$\mathrm{d} s^2=g_{\mu \nu} \mathrm{d} q^{\mu} \mathrm{d} q^{\nu}.$$
I've given the derivation of this in the Cartan calculus also in my previous posting.
In the Ricci calculus the ##\mathrm{d} q^{\mu}## are simply infinitesimal increments of the coordinates and thus
$$\mathrm{d} s^2=g_{\mu \nu} \mathrm{d} q^{\mu} \mathrm{d} q^{\nu}.$$
I've given the derivation of this in the Cartan calculus also in my previous posting.