Meaning of subscript in partial derivative notation

Click For Summary
The subscript "T" in the notation ##\Big(\frac{\partial P}{\partial V}\Big)_T## indicates that the partial derivative of pressure (P) with respect to volume (V) is being calculated while keeping temperature (T) constant. This means that when differentiating P, the values of x and R are treated as constants, along with T. The equation can be rewritten to clarify that P is a function of V and T, allowing for the differentiation to be evaluated at a specific volume. The discussion also highlights the importance of specifying which variables are held constant to avoid ambiguity in multi-variable functions. Understanding this notation is crucial for correctly interpreting and solving problems in thermodynamics and related fields.
kaashmonee
Messages
7
Reaction score
1

Homework Statement


I'm given a gas equation, ##PV = -RT e^{x/VRT}##, where ##x## and ##R## are constants. I'm told to find ##\Big(\frac{\partial P}{\partial V}\Big)_T##. I'm not sure what that subscript ##T## means?

Homework Equations


##PV = -RT e^{x/VRT}##

Thanks a lot in advance.
 
Physics news on Phys.org
kaashmonee said:

Homework Statement


I'm given a gas equation, ##PV = -RT e^{x/VRT}##, where ##x## and ##R## are constants. I'm told to find ##\Big(\frac{\partial P}{\partial V}\Big)_T##. I'm not sure what that subscript ##T## means?

Homework Equations


##PV = -RT e^{x/VRT}##

Thanks a lot in advance.
Firstly, in order to make sense of the notation ##\dfrac{\partial P}{\partial V}## it seems, that ##P## is a function of ##V## and other variables. I assume they all are pressure, volume and temperature. Usually I would say ##\left( \dfrac{\partial P}{\partial V} \right)_T## would mean ##\left( \left. \dfrac{\partial P}{\partial V}\right|_{V=V_0} \right)## which is the partial derivative evaluated at the point ##V=V_0##. But as temperature ##T## is hardly a volume, it means probably something else in this context. My guess would simply be ##\left( \dfrac{\partial P}{\partial V} \right)_T = \dfrac{\partial}{\partial V} P(V,T)## stretching that ##T## is constant here for the differentiation, but a variable for the resulting derivative. If evaluated at say ##V=V_0##, then it is ##\left( \dfrac{\partial P}{\partial V} \right)_T= \left( \left. \dfrac{\partial P}{\partial V}\right|_{V=V_0} \right) (V_0,T)##, i.e. the partial derivative at a certain point ##V_0## for the volume, leaving it a function of temperature ##T##.
 
I'm going to disagree with @fresh_42 here. It most likely means the partial of P with respect to V, but holding T constant.

From Wikpedia, https://en.wikipedia.org/wiki/Partial_derivative#Notation,
When dealing with functions of multiple variables, some of these variables may be related to each other, thus it may be necessary to specify explicitly which variables are being held constant to avoid ambiguity. In fields such as statistical mechanics, the partial derivative of ##f## with respect to ##x##, holding ##y## and ##z## constant, is often expressed as
$$\left(\frac{\partial f}{\partial x}\right)_{y, z} $$
For the partial you're asking about, you could rewrite the equation as ##P = \frac{-RTe^{x/V RT}}{V}##. I'm not sure exactly what your equation is supposed to be as it's ambiguous -- is the exponent on e ##\frac x {VRT}## or is it ##\frac x V RT##? If it's the former, it should have been written as ##e^{x/(VRT)}##. If it's the latter, it would be clearer as ##e^{(x/V)RT}##.
In any case, you now have P as the dependent variable, and V as the only independent variable, with x, R, and T being or acting as constants.
 
Last edited:
  • Like
Likes Marc Rindermann
kaashmonee said:

Homework Statement


I'm given a gas equation, ##PV = -RT e^{x/VRT}##, where ##x## and ##R## are constants. I'm told to find ##\Big(\frac{\partial P}{\partial V}\Big)_T##. I'm not sure what that subscript ##T## means?

Thanks a lot in advance.
it means that you evaluate the differentiation and keep ##T## constant. Similarly you could find ##\left(\frac{\partial P}{\partial T}\right)_V## where you would treat ##V## as a constant
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

Similar threads

  • · Replies 10 ·
Replies
10
Views
2K
Replies
4
Views
1K
Replies
4
Views
1K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
2
Views
1K
Replies
5
Views
4K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K