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## Homework Statement

Hi. I post part A too but I'm having trouble only with Part B.

Question.[PLAIN]http://img100.imageshack.us/img100/8297/20104ivwhytangenttoseco.png [Broken]

## Homework Equations

I know....

[itex]y = sin x [/itex] and [itex] y = cx[/itex] intersects when ...

[itex]sin x = cx[/itex] so [itex] \frac{sin x}{x} = c[/itex]

## The Attempt at a Solution

I just don't understand why [itex] \frac{sin x}{x} = c[/itex]

means that [itex] y = c [/itex] has to be tangent to

[itex] y = \frac{sin x}{x}[/itex] at the second hump?

I'm not seeing the connection...

Thank you.

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