Measure for momentum in curved space

Click For Summary
SUMMARY

The discussion centers on the treatment of momentum space in the context of quantum fields in curved spacetime. It is established that when integrating over momentum space, one should not divide by the square root of the metric determinant, g, as momentum space is fundamentally a Fourier transform independent of the metric structure. Additionally, the use of plane waves in curved spacetime is deemed inappropriate due to their failure to satisfy the Klein-Gordon equation in such contexts. The invariance of integrals over momentum and position spaces is highlighted, indicating that the square root of g in the spatial integral cancels with its inverse in the momentum integral.

PREREQUISITES
  • Understanding of quantum field theory concepts, particularly T^00 and expectation values.
  • Familiarity with curved spacetime and its implications on physical theories.
  • Knowledge of the Klein-Gordon equation and its solutions in various contexts.
  • Experience with Fourier transforms and their application in physics.
NEXT STEPS
  • Study the implications of the Klein-Gordon equation in curved spacetime.
  • Research the properties of Fourier transforms in the context of quantum field theory.
  • Examine the concept of invariance in integrals over curved spaces.
  • Review literature on the density of states in curved space, including the referenced articles.
USEFUL FOR

Physicists, particularly those specializing in quantum field theory and general relativity, as well as researchers exploring the implications of curved spacetime on quantum mechanics.

Judithku
Messages
4
Reaction score
0
When I write down a quantum field (for instance to compute T^00 or some expectation value)

I write it as an integral over momentum space.

If I am working in curved space
should this be divided by sqrt [g]?

(and why or why not?)
 
Physics news on Phys.org
The answer is - no. The "momentum" space can be thought of just as a Fourier transform, which has nothing to do with a metric structure of spacetime.

Moreover, expansion of the field in terms of plane waves is not a natural thing to do in curved spacetime, because plane waves are not solutions of the Klein-Gordon equation in curved spacetime.
 
Thanks -
I realize in general plane waves are inappropriate but I thought in dealing with a very weak potential that they could be used.

In papers written about the density of states in curved space, they say
\int d^3 x \int d^3 p
is invariant.
I thought this meant that the \sqrt g in the space integral cancels out
with its inverse in the momentum integral.
Do you think that is incorrect?
See for instance
http://www.sciencedirect.com/science/article/pii/0375960189905628
and on the arxiv
http://arxiv.org/abs/1012.5421
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 24 ·
Replies
24
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 0 ·
Replies
0
Views
2K