# Measure the distance to a star using magnitude and extinction

Mikkel
Homework Statement:
Measure distance using magnitude and extinction
Relevant Equations:
m - M = 5log_{10}(d/10 pc) + 10^{-3}
Hello, I'm struggling with this question
• A star is observed close to the center of the Milky Way and from its spectrum we find that it is a type A3 star. Its observed magnitude is m_v = 25. There is only a diffusive gas between us and the star, so we can assume an extinction, of 1 magnitude per 1 kpc.
• How far away is the star and what is its (un-redded) magnitude?
• In the H-band, which is 1.63 , the reddening law is . How big is the reddening in the H-band?

I think I got the generel idea right for this problem, but I must be messing up my SI units somewhere. I use the distance formula when working with magnitudes and extinction. I look up the absolute magnitude for a type A3 star, which is roughly 2. I solve for d and end up with a distance of 398kpc, which doesn’t make sense, as the star is at the center of the Milky Way.
I use this formula and I divide A by 10^3 to get units of pc.

I hope someone can spot my mistake

The last term should be d/1000, not 1/1000.
NSolve[25-2.0 == 5*Log10[d/10]+d/1000, d] gives d -> 8383. About 8 kpc.

Mikkel
Mikkel
Why should I multiply by d when considering the extinction term?

Why should I multiply by d when considering the extinction term?

The extinction is 1 magnitude per kpc. So the farther away the star is, the more it's brightness is diminished. This is because you are looking through dust that absorbs the light from the star. The farther away the star is, the more dust is between you and the star, and the more light is absorbed. The way you had it, the extinction would be the same regardless of how far away the star is.

Last edited:
Mikkel
The extinction is 1 magnitude per kpc. So the farther away the star is, the more it's brightness is diminished. The way you had it, the extinction would be the same regardless of how far away the star is.
Ahh yea that makes sense, thank you very much!
Do you perhaps have a clue for the other question as well?

Ahh yea that makes sense, thank you very much!
Do you perhaps have a clue for the other question as well?
Y ou should be able to find the unreddened magnitude. The last question isn't complete.

Mikkel
whoops.. sorry

• In the H-band, which lies in 1.63 μm , the reddening law is A_H = 0.591 E_{B-V}. How big is the reddening in the H-band?
I'm not sure that the "reddening" is in terms of symbol? Not sure how to list it.